I typed right on the problem set.
The answer would be 25t^2 + 40t + 16
There are
ways of drawing a 4-card hand, where

is the so-called binomial coefficient.
There are 13 different card values, of which we want the hand to represent 4 values, so there are
ways of meeting this requirement.
For each card value, there are 4 choices of suit, of which we only pick 1, so there are
ways of picking a card of any given value. We draw 4 cards from the deck, so there are
possible hands in which each card has a different value.
Then there are
total hands in which all 4 cards have distinct values, and the probability of drawing such a hand is

We have that
<span>p(t)=-3t^2+18t-4
using a graphing tool, we can see the maximum of the graph
(see the attached figure)
A) </span><span>In what year of operation does Mr. Cash’s business show maximum profit?
</span>
Mr. Cash’s business show maximum profit at year 3 (maximum in the parabole)
<span>B) What is the maximum profit?
23 (hundred of thousand of dollars) = 2.300.000 dollars
</span>c) What time will it be two late?
(This is the time when the graph crosses zero and the profits turn into losses )
5.77 years, or an estimate of about 69 months.
Answer:
c= 3
Step-by-step explanation:
0.2(10 -5c)= 5c -16
<em>Expand</em><em>:</em>
0.2(10) +0.2(-5c)= 5c -16
2 -c= 5c -16
<em>Bring</em><em> </em><em>all</em><em> </em><em>c</em><em> </em><em>terms</em><em> </em><em>to</em><em> </em><em>1</em><em> </em><em>side</em><em>,</em><em> </em><em>constant</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>other</em><em>:</em>
5c +c= 2 +16
<em>Simplify</em><em>:</em>
6c= 18
<em>Divide</em><em> </em><em>by</em><em> </em><em>6</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>:</em>
c= 18 ÷6
c= 3