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blagie [28]
3 years ago
13

Sin ( 90 + theta ) = cos theta prove^

Mathematics
1 answer:
liberstina [14]3 years ago
5 0
We will use additional formula:
sin ( 90°+ theta ) = sin 90° * cos(theta) + cos 90° * sin(theta)=
= 1 * cos(theta) + 0 * sin(theta)= cos (theta)           It is proved.
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I need this answered asap i will mark brainliest.
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I typed right on the problem set.

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3 years ago
Simplify the product of the binomial. (5t+4)^2
krek1111 [17]
The answer would be 25t^2 + 40t + 16
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If you draw four cards at random from a standard deck of 52 cards, what is the probability that all 4 cards have distinct charac
mezya [45]

There are \binom{52}4 ways of drawing a 4-card hand, where

\dbinom nk = \dfrac{n!}{k!(n-k)!}

is the so-called binomial coefficient.

There are 13 different card values, of which we want the hand to represent 4 values, so there are \binom{13}4 ways of meeting this requirement.

For each card value, there are 4 choices of suit, of which we only pick 1, so there are \binom41 ways of picking a card of any given value. We draw 4 cards from the deck, so there are \binom41^4 possible hands in which each card has a different value.

Then there are \binom{13}4 \binom41^4 total hands in which all 4 cards have distinct values, and the probability of drawing such a hand is

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4 0
2 years ago
The profits of mr cash’s company is represented by the equation p(t)=-3t^2+18t-4, where p(t) is the amount of profit in hundreds
eduard
We have that

<span>p(t)=-3t^2+18t-4

using a graphing tool, we can see the maximum of the graph
(see the attached figure)

A) </span><span>In what year of operation does Mr. Cash’s business show maximum profit?

</span>Mr. Cash’s business show maximum profit at year 3 (maximum in the parabole)

<span>B) What is the maximum profit? 

23 (hundred of thousand of dollars) = 2.300.000 dollars

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4 0
3 years ago
0.2(10-5c)=5c-16 halp
iogann1982 [59]

Answer:

c= 3

Step-by-step explanation:

0.2(10 -5c)= 5c -16

<em>Expand</em><em>:</em>

0.2(10) +0.2(-5c)= 5c -16

2 -c= 5c -16

<em>Bring</em><em> </em><em>all</em><em> </em><em>c</em><em> </em><em>terms</em><em> </em><em>to</em><em> </em><em>1</em><em> </em><em>side</em><em>,</em><em> </em><em>constant</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>other</em><em>:</em>

5c +c= 2 +16

<em>Simplify</em><em>:</em>

6c= 18

<em>Divide</em><em> </em><em>by</em><em> </em><em>6</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>:</em>

c= 18 ÷6

c= 3

5 0
3 years ago
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