Write the equation of a line that is perpendicular to the given line and that passes through the given point.
1 answer:
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Answer:
<em>The point lies barely outside of the circle</em>
Step-by-step explanation:
<u>Equation of a Circle</u>
Given its center (h,k) and radius r, the equation of a circle is given by
The circle given in the question is centered at (7,8) and has a radius of 6, thus its equation is
To find out if a point (a,b) is outside or inside the circle area, the following conditions apply.
if then the point lies outside of the circle area
if then the point lies inside of the circle area
Let's use the point as given (6,2)
Thus the point lies barely outside of the circle
It has been given that y varies inversely with x, therefore the equation for this relationship is as follows;
y =
\
when y = -18 and x = 6
-18 = k/ 6 ---1)
We need to find x when y = 5
5 = k/x
when we divide 1)/2), k gets cancelled
x = -18*6/5
x = -21.6
when y = 5, then x = -21.6
y =
when y = -18 and x = 6
-18 = k/ 6 ---1)
We need to find x when y = 5
5 = k/x
when we divide 1)/2), k gets cancelled
x = -18*6/5
x = -21.6
when y = 5, then x = -21.6