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Ne4ueva [31]
3 years ago
13

Point R lies on the directed line segment from L (-8,-10) to M (4,-2) and partitions the segment in the ratio 3 to 5. What are t

he coordinates of point R
Mathematics
2 answers:
Dvinal [7]3 years ago
7 0

Answer:

R = (- 3.5, - 7 )

Step-by-step explanation:

Using the Section formula

x_{R} = \frac{3(4)+5(-8)}{3+5} = \frac{12-40}{8} = \frac{-28}{8} = - 3.5

y_{R} = \frac{3(-2)+5(-10)}{3+5} = \frac{-6-50}{8} = \frac{-56}{8} = - 7

Thus coordinates of R = (- 3.5, - 7 )

Triss [41]3 years ago
7 0

Answer: (-0.8, -5.2)

Step-by-step explanation:

The coordinates of point P(x,y) divides a line segment with endpoints A(a,b) and B(c,d) in ration m:n is given by :-

x=\dfrac{mc+na}{m+n}\ ;\ n=\dfrac{md+nb}{m+n}

Given : Point R lies on the directed line segment from L (-8,-10) to M (4,-2) and partitions the segment in the ratio 3 to 5.

i.e. \dfrac{m}{m+n}=\dfrac{3}{3+2}

i.e. m:n = 3:2

The coordinates of R divide directed line segment from L (-8,-10) to M (4,-2) in ratio 3:2 will be :-

x=\dfrac{3(4)+2(-8)}{3+2}\ ;\ y=\dfrac{3(-2)+2(-10)}{3+2}\\\\ x=\dfrac{12-16}{5}\ ;\ y=\dfrac{-6-20}{5}\\\\ x=-0.8\ ;\ y=-5.2

The coordinates of R= (-0.8, -5.2)

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So that means we have EF parallel to CD (due to the same side interior angle theorem)

--------------

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