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NNADVOKAT [17]
3 years ago
10

PLEASE HELP!!

Mathematics
2 answers:
LenKa [72]3 years ago
7 0

Answer:

First blank - 33%

Second blank - 36%

Step-by-step explanation:

We are given the table,

                            Pet          No Pet          Total

Apartment            18              36                54

House                   43             24                67

Total                      61              60               121

Now, the conditional probability of an event A, given event B is P(A|B),

where P(A|B)=\frac{P(A\bigcap B)}{P(B)}.

So, we have,

Probability of people living in the apartment having a pet is given by,

P(Having\ a\ pet|Living\ in\ apartment)=\dfrac{P(Having\ a\ pet\bigcap Living\ in\ apartment)}{P(Living\ in\ apartment)}\\\\P(Having\ a\ pet|Living\ in\ apartment)=\dfrac{18}{54}\\\\P(Having\ a\ pet|Living\ in\ apartment)=0.33

<h3>That is, Probability of people living in the apartment having a pet is 33%.</h3>

Also, Probability of people living in the house having no pet is given by,

P(Having\ no\ pet|Living\ in\ house)=\dfrac{P(Having\ no\ pet\bigcap Living\ in\ house)}{P(Living\ in\ house)}\\\\P(Having\ no\ pet|Living\ in\ house)=\dfrac{24}{67}\\\\P(Having\ no\ pet|Living\ in\ house)=0.36

<h3>That is, Probability of people living in the house having no pet is 36%.</h3>
I am Lyosha [343]3 years ago
3 0
36 + 18 = 54

(1) 18/54 = 1/3 = 33%

43 + 24 = 67

(2) 24/67 = 36%




I hope these are right
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