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Harman [31]
3 years ago
5

A ball is thrown into the air with an upward velocity of 36 ft/s. Its height h in feet after t seconds is given by the function

h = −16t2 + 36t + 5. In how many seconds does the ball reach its maximum height? Round to the nearest hundredth if necessary. What is the ball’s maximum height?
A. 2.25 s; 5 ft


B. 1.13 s; 25.25 ft


C. 1.13 s; 27.5 ft


D. 1.13 s; 65.75 ft
Mathematics
1 answer:
Ivenika [448]3 years ago
7 0
<span>A ball is thrown into the air with an upward velocity of 36 ft/s. Its height h in feet after t seconds is given by the function h = −16t2 + 36t + 5. In how many seconds does the ball reach its maximum height? Round to the nearest hundredth if necessary. What is the ball’s maximum height?


A. 2.25 s; 5 ft


B. 1.13 s; 25.25 ft


C. 1.13 s; 27.5 ft


D. 1.13 s; 65.75 ft <====

</span>
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The function can be solved as follows:

  • f(6 + 4) = 25
  • f(6) - f(4) = 20
  • f(6 - 4) = 1
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<h3>How to solve function?</h3>

f(x) = 3x - 5

Therefore, the function can be solved as follows:

f(6 + 4) = f(10) = 3(10) - 5 = 25

f(6) + f(4) = 3(6) - 5 + (3(4) - 5)

f(6) - f(4) = 13 + 7

f(6) - f(4) = 20

f(6 - 4) = f(2) = 3(2) - 5 = 6 - 5 = 1

f(6) - f(4) = 3(6) - 5 - (3(4) - 5)

f(6) - f(4) = 18 - 5  - (12 - 5)

f(6) - f(4) = 13 - 7

f(6) - f(4) = 6

f(6.4) = f(24) = 3(24) - 5 = 72 - 5 = 67

f(6) . f(4) = (3(6) - 5 ) (3(4) - 5)

f(6) . f(4) = (18 - 5)(12 - 5)

f(6) . f(4) = (13)(7) = 91

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<h3>Answer:   g(f(x)) = 4x^2 - 4x - 3</h3>

Work Shown:

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g(f(x)) = ( 2x-1 )^2 - 4

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g(f(x)) = 4x^2-2x-2x+1 - 4

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