All categories

3 years ago

How do u do #10? Plz show on paper

Mathematics

1 answer:

Studentka2010 [4]3 years ago

3 0

Reflection across the line y=x simply swaps the x and y coordinates.
K'(-2, -5), A'(1, -4), I'(-1, 0), J'(-4, -2)

You might be interested in

Does the point (8,0) lie on the line represented by 3x + 2y = 16?<br> O True<br> False

Sliva [168]

Answer:

false

Step-by-step explanation:

(0,8) is on the line, not (8,0) :)

4 0

3 years ago

What value from the set {6, 7, 8, 9, 10} makes the equation 5x + 2 = 47 true? Show your work.

vivado [14]

5x+2=47 subtract 2 from both sides

5x=45 divide both sides by 5

x=9

5 0

3 years ago

Solve the following using the elimination or substitution method. Show all work.

ki77a [65]

Jim has 28 nickels and 37 dimes in his pocket. which is determined by the substitution method.

<h3>What is the equation?</h3>

The term "equation" refers to mathematical statements that have at least two terms with variables or integers that are equal.

Let the number of nickels would be n

Let the number of dimes would be d

As per the given question,

d + n = 65 ....(i)

0.10d + 0.05n = 5.10 ....(ii)

From equation (i),

d + n = 65

d + n - n = 65 - n

d = 65 - n

Substitute in for the equation(ii): d = 65 - n

0.10(65 - n) + 0.05n = 5.10

6.5 - 0.10n + 0.05n = 5.10

6.5 - 0.05n = 5.10

6.5 - 0.05n - 6.5 = 5.10 - 6.5

- 0.05n = -1.4

n = 28

This means there are 28 nickels

Substitute the value of n = 28 in the equation (i),

d + n = 65

d + 28 = 65

d = 37

So there are 37 dimes

Thus, Jim has 28 nickels and 37 dimes in his pocket.

Learn more about the equation here:

brainly.com/question/10413253

#SPJ2

3 0

1 year ago

Read 2 more answers

(43 points) In the US, 85% of the population has Rh positive blood. Suppose we take a random sample of 6 persons and let Y denot

VladimirAG [237]

Answer:

a) Binomial distribution with parameters p=0.85 q=0.15 n=6

b) 62.29%

c) 2.38%

d) See explanation below

Step-by-step explanation:

We could model this situation with a binomial distribution

$P(6;k)=\binom{6}{k}p^kq^{6-k}$

where P(6;k) is the probability of finding exactly k people out of 6 with Rh positive, p is the probability of finding one person with Rh positive and q=(1-p) the probability of finding a person with no Rh.

$\bf P(Y=k)=\binom{6}{k}(0.85)^k(0.15)^{6-k}$

The probability that Y is less than 6 is

P(Y=0)+P(Y=1)+...+P(Y=5)

Let's compute each of these terms

$P(Y=0)=P(6;0)=\binom{6}{0}(0.85)^0(0.15)^{6}=1.139*10^{-5}$

$P(Y=1)=P(6;1)=\binom{6}{1}(0.85)^1(0.15)^{5}=0.0000387281$

$P(Y=2)=P(6;2)=\binom{6}{2}(0.85)^2(0.15)^{4}=0.005486484$

$P(Y=3)=P(6;3)=\binom{6}{3}(0.85)^3(0.15)^{3}=0.041453438$

$P(Y=4)=P(6;4)=\binom{6}{4}(0.85)^4(0.15)^{2}=0.176177109$

$P(Y=5)=P(6;5)=\binom{6}{5}(0.85)^5(0.15)^{1}=0.399334781$

and adding up these values we have that the probability that Y is less than 6 is

$\sum_{i=1}^{5}P(Y=i)=0.622850484\approx 0.6229=62.29\%$

In this case is a binomial distribution with n=200 instead of 6.

p and q remain the same.

The mean of this sample would be 85% of 200 = 170.

In a binomial distribution, the standard deviation is

$s = \sqrt{npq}$

In this case

$\sqrt{200(0.85)(0.15)}=5.05$

<em>Let's approximate the distribution with a normal distribution with mean 170 and standard deviation 5.05</em>

So, the approximate probability that there are fewer than 160 persons with Rh positive blood in a sample of 200 would be the area under the normal curve to the left of 160

(see picture attached)

We can compute that area with a computer and find it is

0.0238 or 2.38%

d)<em> In order to approximate a binomial distribution with a normal distribution we need a large sample like the one taken in c).</em>

In general, we can do this if the sample of size n the following inequalities hold:

$np\geq 5 \;and\;nq \geq 5$