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rjkz [21]
3 years ago
11

Solve using quadratic formula. X^2+9x-13=0

Mathematics
1 answer:
MatroZZZ [7]3 years ago
7 0
I hope this helps you

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Factor the trinomial completely. 10x^2+7x-12
musickatia [10]

Answer: i think the answer is (5x - 4)(2x +3) if it id wrong i am sorry ok

don't forget to drop a heart

4 0
3 years ago
Read 2 more answers
If 3/8 of my money is $3840.00. How much did I have at first? *
NNADVOKAT [17]

Answer:

E $10240.00

Step-by-step explanation:

The total amount of money is x.

3/8 × x = 3840

Multiply both sides by the reciprocal of 3/8 which is 8/3.

x = 3840 × 8/3

x = 10240

Answer: E $10240.00

7 0
2 years ago
Read 2 more answers
XY is a diameter of a circle and Z is a point on the circle such that ZY=6. If the area of the triangle XYZ is 18 square root 3
nataly862011 [7]
<h2>Answer:</h2>

4π

<h2>Step-by-step explanation:</h2>

As shown in the diagram, triangle XYZ is a right triangle. Therefore, its area (A) is given by:

A = \frac{1}{2} x b x h      -------------(i)

Where;

A = 18\sqrt{3}

b = XZ = base of the triangle

h = YZ = height of the triangle = 6

<em>Substitute these values into equation(i) and solve as follows:</em>

18\sqrt{3} =  \frac{1}{2} x b x 6

18\sqrt{3} =  3b

<em>Divide through by 3</em>

6\sqrt{3} =  b

Therefore, b = XZ = 6\sqrt{3}

<em>Now, assume that the circle is centered at O;</em>

Triangle XOZ is isosceles, therefore the following are true;

(i) |OZ| = |OX|

(ii) XZO = ZXO = 30°

(iii) XOZ + XZO + ZXO = 180°   [sum of angles in a triangle]

=>  XOZ + 30° + 30° = 180°

=>  XOZ + 60° = 180°

=>  XOZ = 180° - 60°

=>  XOZ = 120°

Therefore we can calculate the radius |OZ| of the circle using sine rule as follows;

\frac{sin|XOZ|}{XZ} = \frac{sin|ZXO|}{OZ}

\frac{sin120}{6\sqrt{3} } = \frac{sin 30}{OZ}

\frac{\sqrt{3} /2}{6\sqrt{3} } = \frac{1/2}{|OZ|}

\frac{1}{12}  = \frac{1}{2|OZ|}

\frac{1}{6} = \frac{1}{|OZ|}

|OZ| = 6

The radius of the circle is therefore 6.

<em>Now, let's calculate the length of the arc XZ</em>

The length(L) of an arc is given by;

L = θ / 360 x 2 π r          ------------------(ii)

Where;

θ = angle subtended by the arc at the center.

r = radius of the circle.

In our case,

θ = ZOX = 120°

r = |OZ| = 6

Substitute these values into equation (ii) as follows;

L = 120/360 x 2π x 6

L = 4π

Therefore the length of the arc XZ is 4π

5 0
3 years ago
Solve for y. <br><br> xy + p = 5<br><br> A) y = 5 - p - x<br> B) y = (5-p)/x<br> C) y = 5 - px
Damm [24]
Minus p both sides
xy=5-p
divide both sides by x
y=(5-p)/x

B
6 0
3 years ago
A table is on sale for $403, which is 38% less than the regular price. what is the regular price
Nesterboy [21]
1060.5263157 etc your teacher prob tells you to round 
4 0
3 years ago
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