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3 years ago

6

A scientist is conducting an experiment on two types of bacteria to determine which type will grow faster in a pool. After colle

cting data for two weeks, she finds that she can model the growth rates as follows: Bacteria 1: y = 4x Bacteria 2: y = 4x2 In these models, y represents the number of bacteria colonies and x represents the number of hours. Based on these models, which type of bacteria is growing faster? bacteria 1

2 answers:

Igoryamba3 years ago

7 0

Answer:

bacteria 1

Step-by-step explanation:

hope this helped:)

Allushta [10]3 years ago

5 0

Answer: bacteria 2

Step-by-step explanation:

Since the growth rates are modeled as : Bacteria 1: y = 4x

And Bacteria 2: y = 4x2

Where y represents the number of bacteria colonies and x represents the number of hours.

Let's plug in for the two models

By assuming x = 2 and x = 3

If x = 2

Bacteria 1 will be y = 8 and bacteria 2 will be y = 16

Based on these models, bacteria 2 is growing faster than bacteria 1 because the growth is exponential

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Cerrena [4.2K]

I believe the answer is C

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3 years ago

(b) how many measurements must be averaged to get a margin of error of ±0.0001 with 98% confidence? (round your answer up to the

goblinko [34]

Given that the scale readings of the laboratory scale is normally distributed with an unknown mean and a standard deviation of 0.0002 grams.

Part A:

If the weight is weighted 5 times and the mean weight is 10.0023 grams, the 98% confidence interval for μ, the true mean of the scale readings is given by:

$98\% \ C. \ I.=\bar{x}\pm z_{\alpha/2}\left(\frac{\sigma}{\sqrt{n}}\right) \\ \\ =10.0023\pm2.33\left(\frac{0.0002}{\sqrt{5}}\right) \\ \\ =10.0023\pm2.33(0.000089) \\ \\ =10.0023\pm0.00021 \\ \\ =(10.0023-0.00021, \ 10.0023+0.00021) \\ \\ =(10.0021, \ 10.0025)$

Thus, we are 98% confidence that the true mean of the scale readings is between 10.0021 and 10.0025.

Part B:

To get a margin of error of +/- 0.0001 with a 98% confidence, then

$\pm z_{\alpha/2}\left(\frac{\sigma}{\sqrt{n}}\right)=\pm0.0001 \\ \\ \Rightarrow2.33\left(\frac{0.0002}{\sqrt{n}}\right)=0.0001 \\ \\ \Rightarrow\left(\frac{0.0002}{\sqrt{n}}\right)= \frac{0.0001}{2.33} =0.0000429 \\ \\ \Rightarrow\sqrt{n}= \frac{0.0002}{0.0000429} =4.66 \\ \\ \Rightarrow n=4.66^2=21.7156\approx22$

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8 0

3 years ago

The angle measurements in the diagram are represented by the following expressions

AURORKA [14]

Answer:

∠ B = 45°

Step-by-step explanation:

∠ A and ∠ Bare alternate exterior angles and are congruent , then

5x - 15 = 2x + 21 ( subtract 2x from both sides )

3x - 15 = 21 ( add 15 to both sides )

3x = 36 ( divide both sides by 3 )

x = 12

Then

∠ B = 2x + 21 = 2(12) + 21 = 24 + 21 = 45°

6 0

3 years ago

8. SOLVE THE EQUATION BELOW

Naddik [55]

Answer:

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Step-by-step explanation:

m/(np²)=k

m=knp²

m/(kp²)=n

E) m/(kp²)=n Gorilla Costumes

8 0

3 years ago

Read 2 more answers

Please help me! I'm stuck and really confused, thank you so much!

Kryger [21]

Answer:

(a) $5 * (2x - 1) = 10x - 5$

(b) $6 * x = x + 2x + 3x$

(c) $\frac{1}{2}(x - 6) = \frac{1}{2}x - 3$

(d) $y(3x + 4z) = 3xy + 4yz$

(e) $z(2xy - 3y + 4x) = 2xyz - 3yz + 4xz$

Step-by-step explanation:

Solving (a):

Given

$10x - 5$

Required

Express as a product

Express 10x as 5 * 2x

$10x - 5 = 5 * 2x - 5$

Apply distributive property

$10x - 5 = 5(2x - 1)$

$10x - 5 = 5 * (2x - 1)$

So:

$5 * (2x - 1) = 10x - 5$

Solving (b):

Given

$x + 2x + 3x$

Required

Express as a product

Express 2x and 3x as 2 * x and 3 * x, respectively

$x + 2x + 3x = x + 2*x + 3*x$

Apply distributive property

$x + 2x + 3x = x(1 + 2 + 3)$

$x + 2x + 3x = x(6)$

$x + 2x + 3x = 6*x$

So:

$6 * x = x + 2x + 3x$

Solving (c):

Given

$\frac{1}{2}(x - 6)$

Required

Express as a sum/difference

Apply distributive property

$\frac{1}{2}(x - 6) = \frac{1}{2}x - \frac{1}{2}*6$

$\frac{1}{2}(x - 6) = \frac{1}{2}x - \frac{6}{2}$

$\frac{1}{2}(x - 6) = \frac{1}{2}x - 3$

Solving (d):

Given

$y(3x + 4z)$

Required

Express as a sum/difference

Apply distributive property

$y(3x + 4z) = 3x * y + 4z * y$

$y(3x + 4z) = 3xy + 4yz$

Solving (e):

Given

$2xyz - 3yz + 4xz$

Required

Express as a product

Factorize

$2xyz - 3yz + 4xz = 2xy * z - 3y * z + 4x * z$

Apply distributive property

$2xyz - 3yz + 4xz = z(2xy - 3y + 4x)$

So:

$z(2xy - 3y + 4x) = 2xyz - 3yz + 4xz$

8 0

3 years ago