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professor190 [17]
3 years ago
7

Find two consecutive even integers such that the sum of the smaller and 3 times the larger is 330

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
4 0

Answer:

The 2 numbers = 81 and 83

Step-by-step explanation:

As, one number = x

The other, because it's an even number and consecutive = x + 2

So the larger numbef here is x + 2

And they are saying 3 times x + 2 plus x = 330

So let's solve!

3 times x + 2 = 3(x+2) = 3x + 6

So we will add it to x = (3x + 6) +(x) = 4x + 6

So they are saying the sum of them will be 330

So, 4x + 6 = 330

4x = 330 - 6

4x = 324

x = 324/4

x = 81

So x is the first number = 81

And the second is x + 2 = 81 + 2 = 83

So the 2 numbers are 81, 83

Lets check!

3 times the bigger number = 83 x 3 = 249

We will add it to 81 and we will get 330

So, 249 + 81 = 330

So the answer is right

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If M is the set of all perfect squares that are less than 100 and N is the set of all positive numbers that are less than 15. wr
deff fn [24]

The sets of M and N are { 4 , 16 , 25 , 36 , 49 , 64 , 81 } and{ 0, 1 , 2 , 3, 4, 5 , 6, 7 , 8, 9, 10, 11, 12, 13, 14, 15 }

<h3>What is set?</h3>

Set is a collection of elements or numbers or objects.

It is represented with the symbol '{}'

We have that;

  • M is the set of all perfect squares that are less than 100
  • N is the set of all positive numbers that are less than 15

M = { 4 , 16 , 25 , 36 , 49 , 64 , 81 }

N = { 0, 1 , 2 , 3, 4, 5 , 6, 7 , 8, 9, 10, 11, 12, 13, 14, 15 }

Thus, the sets of M and N are { 4 , 16 , 25 , 36 , 49 , 64 , 81 } and{ 0, 1 , 2 , 3, 4, 5 , 6, 7 , 8, 9, 10, 11, 12, 13, 14, 15 }

Learn more about sets here:

brainly.com/question/2166579

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The length of a rectangle is 5 ft longer than its width. If the perimeter of the rectangle is 38 ft , find its area.
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Ok so basically L=5+w
w=w
P=38
and A=?
well we know that P=all the four sides added so
38=2(5+w)+2w
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38=10+4w
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so if L=w+5 then L=7+5 so L=12
A=LxW so A=12x7 A=84
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