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Fynjy0 [20]
3 years ago
6

Are (121 over 11),(23 over 3), and (85 over 5) in simplest form?

Mathematics
2 answers:
Sedaia [141]3 years ago
5 0
Answers:

121/11=11

23/3=23/3

85/5=17
Allushta [10]3 years ago
5 0
121/11= 11. 23/3= 7 2/3. 85/5= 17.
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This involves creating some equations.

First, these are what the letters I used stand for:

c = children

w = women

m = men

x = total population

Then, we must make an equation for each statement.

2/5x = m (2/5 of the people are men)

3c = w (there are 3 times as many women than children)

45+c = m (there are 45 more men than children)

Now, let's start plugging in our numbers:

x = all the men, women, and children

2/5(m+w+c) = m

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2/5 (45 + 5x) = m       [Now Distribute]

2/5(45) + (2/5)(5x) = m

2c + 18 = m    [Above we stated that there were the same amount as men as c +45]

2c + 18 = 45 +c     [Now set equal to c]

2c (-c) +18 = 45 +c (-c)

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Now that we know that there was 27 children, we can plug 27 in for c in the other equations.

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shtirl [24]

Answer:

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Step-by-step explanation:

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mario62 [17]

Answer:

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Step-by-step explanation:

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