Answer:
3240 pounds of copper would be used
Step-by-step explanation:
![\frac{18}{15}=\frac{x}{2700} \\(2700)*(\frac{18}{15})=x\\3240lbs=x](https://tex.z-dn.net/?f=%5Cfrac%7B18%7D%7B15%7D%3D%5Cfrac%7Bx%7D%7B2700%7D%20%5C%5C%282700%29%2A%28%5Cfrac%7B18%7D%7B15%7D%29%3Dx%5C%5C3240lbs%3Dx)
Answer:
Waste of tree so not halal mode
Answer:
D
Step-by-step explanation:
The difference is 6 and because 6+4=10( 1 wk ),10+4=14( 2 wk ),14+4=18( 3 wk ),18+4=22( 4 wk ),22+4=26( 5 wk ).
Answer:
![0.625kg](https://tex.z-dn.net/?f=0.625kg)
Step-by-step explanation:
we are given half-life of PO-210 and the initial mass
we want to figure out the remaining mass <u>after</u><u> </u><u>4</u><u>2</u><u>0</u><u> </u><u>days</u><u> </u>
in order to solve so we can consider the half-life formula given by
![\displaystyle f(t) = a {0.5}^{t/T}](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20f%28t%29%20%3D%20a%20%7B0.5%7D%5E%7Bt%2FT%7D%20)
where:
- f(t) is the remaining quantity of a substance after time t has elapsed.
- a is the initial quantity of this substance.
- T is the half-life
since it halves every 140 days our T is 140 and t is 420. as the initial mass of the sample is 5 our a is 5
thus substitute:
![\displaystyle f(420)=5\cdot{0.5}^{420/140}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f%28420%29%3D5%5Ccdot%7B0.5%7D%5E%7B420%2F140%7D)
reduce fraction:
![\displaystyle f(420)=5\cdot{0.5}^{3}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f%28420%29%3D5%5Ccdot%7B0.5%7D%5E%7B3%7D)
By using calculator we acquire:
![\displaystyle f(420)=0.625](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f%28420%29%3D0.625)
hence, the remaining sample after 420 days is 0.625 kg
Hello!
The sum of a number and 11:
Let's say that the number is x. So the expression "the sum of a number and x" looks like this:
x+11
Hope this helps you!
~Just an emotional teen who listens to her favourite songs
![SilentNature](https://tex.z-dn.net/?f=SilentNature)