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2 years ago

Find the missing side length, m.

Mathematics

1 answer:

amid [387]2 years ago

4 0

Answer:

m = 5

Step-by-step explanation:

Remark

This is a proportion question. A proportion is 2 equal ratios. There are 4 parts to a proportion. If 3 are known, the 4th can be found.

Formula

AB/AC = RQ/QS

Givens

AB = m

AC = 2

RQ = 10

QS = 4

Solution

m/2 = 10/4 Multiply both sides by 2

2m/2 = 2*10/4 Combine

m = 20/4

m = 5

Answer m = 5

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Can someone help me!!!!!!!!!!!

ipn [44]

Answer:

18 ounces

Step-by-step explanation:

2 x 8 = 16 1/4 x 8 = 8/4 or 2

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3 years ago

Help MOI Again PLEASE lol

Evgesh-ka [11]

Answer:

-5a + 20a +-4a - -6= -16

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Mohamed decided to track the number of leaves on the tree in his backyard each year The first year there were 500 leaves Each ye

svetlana [45]

Answer:

The required recursive formula is

$f(n)= 500\times(1.4)^{n-1}\\$

Step-by-step explanation:

Mohamed decided to track the number of leaves on the tree in his backyard each year.

The first year there were 500 leaves

$Year \: 1 = 500$

Each year thereafter the number of leaves was 40% more than the year before so that means

$Year \: 2 = 500(1+0.40) = 500\times 1.4\\$

For the third year the number of leaves increase 40% than the year before so that means

$Year \: 3 = 500\times 1.4(1+0.40) = 500 \times 1.4^{2}\\$

Similarly for fourth year,

$Year \: 4 = 500\times 1.4^{2}(1+0.40) = 500\times 1.4^{3}\\$

So we can clearly see the pattern here

Let f(n) be the number of leaves on the tree in Mohameds back yard in the nth year since he started tracking it then general recursive formula is

$f(n)= 500\times(1.4)^{n-1}\\$

This is the required recursive formula to find the number of leaves for the nth year.

Bonus:

Lets find out the number of leaves in the 10th year,

$f(10)= 500\times(1.4)^{10-1}\\\\f(10)= 500\times(1.4)^{9}\\\\f(10)= 500\times20.66\\\\f(10)= 10330$

So there will be 10330 leaves in the 10th year.

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3 years ago

Read 2 more answers

Value of log2 8 + log 3(1/3)

Dvinal [7]

There’s no answer choices but i got log(28•3^1/3)

5 0

3 years ago

What are the factors of expression (y-3)(x+7)

torisob [31]

That is easy!! :)
y=3 and x=-7

When you find the factors of something like this, you have to just get the letter alone.

For example: y-3. You have to first write it as y-3=0, then you add 3 from BOTH sides of the = so that you can make the -3 go away and y will be alone. So, it will look like this: y-3+3=0+3. Then, you solve it for y (which just means that you want y by itself on one side of the = ). So, -3+3=0, which means they disappear from that side; since 0+3=3, that's what that side turns into, so what you end up with is y=3

Same thing goes for the x+7 equation:
x+7=0
x+7-7=0-7
x=-7

4 0

3 years ago