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2 years ago

Find the missing side length, m.

Mathematics

1 answer:

amid [387]2 years ago

4 0

Answer:

m = 5

Step-by-step explanation:

Remark

This is a proportion question. A proportion is 2 equal ratios. There are 4 parts to a proportion. If 3 are known, the 4th can be found.

Formula

AB/AC = RQ/QS

Givens

AB = m

AC = 2

RQ = 10

QS = 4

Solution

m/2 = 10/4 Multiply both sides by 2

2m/2 = 2*10/4 Combine

m = 20/4

m = 5

Answer m = 5

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2 years ago

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1) Billy walks 15 miles every day to soccer practice, and catches a ride home from his grandma. Billy had 5 practices last week.

nignag [31]

1 ) Billy walks 15 miles every day to soccer practice and he had 5 practices last week.

We know that, 1 mile = 1760 yards

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2) Mark's current age is $t$ years

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Given that, his current age is 3 times his age 10 years ago.

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3 years ago

Write y=10x as a logarithmic function please

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$\bf \textit{exponential form of a logarithm}
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3 years ago

A population has the following characteristics. (a) A total of 75% of the population survives the first year. Of that 75%, 25% s

Artemon [7]

Answer:

$= \left[\begin{array}{ccc}1344\\84\\28\end{array}\right] \left \begin{array}{ccc}{0 \ \leq age \leq 1 }\\{ 1 \ \leq age \leq 2 }\\{2 \ \leq age \leq 3}\end{array}\right$

i.e after the first year ;

there 1344 members in the first age class

84 members for the second age class; and

28 members for the third age class

Step-by-step explanation:

We can deduce that the age distribution vector x represents the number of population members for each age class; Given that in each class of age there are 112 members present.

The current age distribution vector is as follows:

$x = \left[\begin{array}{ccc}1&1&2\\1&1&2\\1&1&2\end{array}\right] \left[\begin{array}{ccc}{0 \ \leq age \leq 1 }\\{ 0 \ \leq age \leq 2 }\\{0 \ \leq age \leq 3}\end{array}\right]$

Also , the age transition matrix is as follows:

$L = \left[\begin{array}{ccc}3&6&3\\0.75&0&0 \\0&0.25&0\end{array}\right]$

After 1 year ; the age distribution vector will be :

$x_2 =Lx_1 = \left[\begin{array}{ccc}3&6&3\\0.75&0&0 \\0&0.25&0\end{array}\right] \left[\begin{array}{ccc}1&1&2\\1&1&2\\1&1&2\end{array}\right]$

$= \left[\begin{array}{ccc}1344\\84\\28\end{array}\right] \left \begin{array}{ccc}{0 \ \leq age \leq 1 }\\{ 1 \ \leq age \leq 2 }\\{2 \ \leq age \leq 3}\end{array}\right$

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2 years ago

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nika2105 [10]

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