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3 years ago

How much does a 100 degree angle turn through

Mathematics

2 answers:

dsp733 years ago

8 0

Answe

A circle is 360 degrees so if you are turning 100 degrees... you would get 100/360 of the way around the circle.Jan

Step-by-step explanation:

svetlana [45]3 years ago

8 0

Answer A circle is 360 degrees so if you are turning 100 degrees... you would get 100/360 of the way around the circle.:

Step-by-step explanation:

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Suppose you add two vectors A and B . What relative direction between them produces the resultant with the greatest magnitude? W

Anna71 [15]

Answer: The resultant would be the sum and the difference between the vectors.

Step by step explanation: 1. The possible resultant is between the sum of the 2 vectors and the difference between the two vectors.

2. The greatest magnitude is when the vectors lie in the same direction and the sum would be the scalar sum of the two vectors. The angle between the two would be zero degree.

6 0

3 years ago

If a publisher of nontechnical books takes great pains to ensure that its books are free of typos, so that the probability of an

Troyanec [42]

Answer:

(a) 0.2707

(b) 0.8576

Step-by-step explanation:

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3 years ago

AVERAGES 1. Find the mean, mode and median of: (a) 1.5, 1.2, 1.3, 1.5, 1.4 (b) 2.3, 1.2, 2.4, 1.2

NNADVOKAT [17]

Answer:

Look at Step by step

Step-by-step explanation:

Mean: (a) 1.38

Mean: (b) 1.7

median (a) 1.3

Pacx '?

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;zzx';

[c' / v\Zcccccccc

8 0

3 years ago

Read 2 more answers

1. (a) Solve the differential equation (x + 1)Dy/dx= xy, = given that y = 2 when x = 0. (b) Find the area between the two curves

erastova [34]

(a) The differential equation is separable, so we separate the variables and integrate:

$(x+1)\dfrac{dy}{dx} = xy \implies \dfrac{dy}y = \dfrac x{x+1} \, dx = \left(1-\dfrac1{x+1}\right) \, dx$

$\displaystyle \frac{dy}y = \int \left(1-\frac1{x+1}\right) \, dx$

$\ln|y| = x - \ln|x+1| + C$

When x = 0, we have y = 2, so we solve for the constant C :

$\ln|2| = 0 - \ln|0 + 1| + C \implies C = \ln(2)$

Then the particular solution to the DE is

$\ln|y| = x - \ln|x+1| + \ln(2)$

We can go on to solve explicitly for y in terms of x :

$e^{\ln|y|} = e^{x - \ln|x+1| + \ln(2)} \implies \boxed{y = \dfrac{2e^x}{x+1}}$

(b) The curves y = x² and y = 2x - x² intersect for

$x^2 = 2x - x^2 \implies 2x^2 - 2x = 2x (x - 1) = 0 \implies x = 0 \text{ or } x = 1$

and the bounded region is the set

$\left\{(x,y) ~:~ 0 \le x \le 1 \text{ and } x^2 \le y \le 2x - x^2\right\}$

The area of this region is

$\displaystyle \int_0^1 ((2x-x^2)-x^2) \, dx = 2 \int_0^1 (x-x^2) \, dx = 2 \left(\frac{x^2}2 - \frac{x^3}3\right)\bigg|_0^1 = 2\left(\frac12 - \frac13\right) = \boxed{\frac13}$

7 0

2 years ago

Which expression represents 5 less thann twice

Gwar [14]

Answer:

2x -5, like that you didn't put enough.

8 0

3 years ago