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alexgriva [62]
2 years ago
13

Based on the graph, what is the initial value of the linear relationship?

Mathematics
1 answer:
Leya [2.2K]2 years ago
6 0

Answer:

please help me please yh the picture and answers

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PLEASE HELP
uranmaximum [27]

The coordinate for A, B, C, and D: (Current coordinates)

A: (-1, 4)

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C: (-5, 4)

D: (-4, 2)

Once we reflect acorss the y-axis the coordinates become:

A': (1, 4)

B': (5, 8)

C': (5, 4)

D': (4, 2)

In this situation the coordinates just become positive.

I hope this helps!

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The area of a rectangular soccer field is 5000 yd^2. The length of the field is twice the length. Find the dimensions of the fie
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The dimensions of the field are 50 yd by 100 yd.
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3 years ago
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The cumulative distribution function f(x) of a discrete random variable x is given by f(0) =. 30, f(1) =. 70, f(2) =. 90 and f(3
Lisa [10]

Correlation between x & y is 0.6125.

In probability theory and statistics, the cumulative distribution function of a real-valued random variable X, or simply the distribution function of X weighted by x, is the probability that X takes a value less than or equal to x.

The cumulative distribution function (CDF) of a random variable X is defined as FX(x)=P(X≤x) for all x∈R. Note that the subscript X indicates that this is the CDF of the random variable X. Also note that the CDF is defined for all x∈R. Let's look at an example.

Learn more about cumulative distribution here: brainly.com/question/24756209

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7 0
1 year ago
Air containing 0.04% carbon dioxide is pumped into a room whose volume is 6000 ft3. The air is pumped in at a rate of 2000 ft3/m
borishaifa [10]

Answer:

the concentration at 10 minutes= 0.4+0.0133= 0.4133%

Step-by-step explanation:

Air containing 0.04% carbon dioxide

V, volume of room is 6000 ft3.

Q, rate of air 2000 ft3/min,

initial concentration of 0.4% carbon dioxide,

determine the subsequent amount in the room at any time.

What is the concentration at 10 minutes?

firstly, we find the time taken for air to completely filled the room

Q = V/t

t = V/Q = 6000/2000 = 3min

so, its take 3mins for air to be completely filled in the room and for exhaust air to move out.

there is  an initial concentration of 0.4% carbon dioxide, and the air pump in is 0.04%.

therefore,

3mins = 0.04% of CO2

3*60 =180sec = 0.04%

1sec = 0.04/180 = 0.00022%/sec

so at any time the concentration of CO2 is 0.4 + 0.00022 =0.40022%/sec

What is the concentration at 10 minute

the concentration at 10minutes = the concentration for 1minute because at every minutes, the concentration moves in is moves out. = concentration for 2000ft3.

for 0.04% = 6000ft3

   ?          = 2000ft3

              = 2000* 0.04)/6000 =0.0133%

the concentration at 10 minutes= 0.4+0.0133= 0.4133%

4 0
3 years ago
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