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musickatia [10]
3 years ago
15

Consider this function.

Mathematics
2 answers:
Lunna [17]3 years ago
8 0

Answer:

Since the range of the original function is limited to y  6, the domain of the inverse function is x ≥ 6.

Step-by-step explanation:

denis23 [38]3 years ago
6 0

Answer:b

Step-by-step explanation:

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The diagonals of a parallelogram ABCD intersect at O.find ar(AOB),if ar(ABCD)is 44cm^2
prisoha [69]

Answer:

11\text{ cm}^2

Step-by-step explanation:

Given: In a parallelogram ABCD, diagonals intersect at O and ar(ABCD) is 44 \text{cm}^2.

We need to find the area of triangle AOB.

We know that each diagonal divide the parallelogram in two equal parts and diagonals bisect each other.

It means both diagonals divide the parallelogram in 4 equal parts.

ar(AOB)=\dfrac{1}{4}\times ar(ABCD)

ar(AOB)=\dfrac{1}{4}\times 44

ar(AOB)=11

Hence, the values of ar(AOB) is 11\text{ cm}^2.

5 0
3 years ago
One rule of thumb for estimating crowds is that each person occupies 2.3 square feet. Use this value to estimate the size of a c
dybincka [34]

Answer:

150,595

Step-by-step explanation:

First, convert miles to feet:

4.1 mi × (5280 ft/mi) = 21648 ft

The area that the crowd takes up is:

2 × 8 ft × 21648 ft = 346368 ft²

The number of people is:

346368 ft² × (1 person / 2.3 ft²) = 150594.8

Rounding to the nearest integer, there are approximately 150,595 people in the crowd.

7 0
3 years ago
A line with a slope of -10 passes through the points of (10, -7) and (9,j) what is the value of j?
CaHeK987 [17]
So, using our given information, we have a line of the equation y+7=-10(x-10), or y=-10x+93. Plugging in our value 9 for x, we get j = -10(9)+93 = 3.

j=3
7 0
3 years ago
I’ll mark the first person to answer
almond37 [142]

Answer:

$3.00 per person $8.00 per vehicle

Step-by-step explanation:

2x3=6    6+8=14

4x3=12   12+8=20

8x3=24  24+8=32

Hope this helps

4 0
3 years ago
1. Is c=71 a solution to the equation 56 = c - 15 ?
jolli1 [7]

Answer:

1. Yes

2. Yes

3. No

Step-by-step explanation:

7 0
2 years ago
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