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Lerok [7]
3 years ago
14

What are the real roots of 2x^3+9x^2+4x-15=0

Mathematics
1 answer:
klemol [59]3 years ago
8 0
Well, luckily it is apparent that (x-1) is a root because when x=1 the equation is equal to zero.  So we can divide the equation by that factor to find the other roots. 

(2x^3+9x^2+4x-15)/(x-1)
2x^2  r  11x^2+4x-15
11x    r  15x-15
15     r   0

(x-1)(2x^2+11x+15)=0

(x-1)(2x^2+6x+5x+15)=0

(x-1)(2x(x+3)+5(x+3))=0

(x-1)(2x+5)(x+3)=0

So the roots are x= -3, -2.5, 1
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3 years ago
Find the value of 40% of 1KM (in m)​
labwork [276]

40% of 1 km in meters is 400 meters

<h3>What is percentage :</h3>

Percentage simply means per 100. Percentage can be express as decimal or fraction.

For example 25% of 80 can be found as follows:

  • 25 / 100 × 80 = 2000 / 100 = 20

From the example, 25% of 80 is 20 .

Therefore, 40% of 1 km(m) can be found as follows:

Let's convert km to metres.

1000m = 1km

40% of 1000

40 / 100 × 1000 = 40000 / 100 = 400metres

Therefore, 40% of 1 km in meters is 400 meters

learn more on percentage here: brainly.com/question/19540991?referrer=searchResults

5 0
2 years ago
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Answer:

The answer is 113

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36 + 7(11)

36 + 77  

113

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2 years ago
Are these functions?
OlgaM077 [116]

Answer:

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Mr. Jones is getting a 6% raise. If he made $720 a week, how much more will he make with the raise?
kirill115 [55]

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He will make $43.20 more each week.

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