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3 years ago

8

Rachel rode her bike for one-fifth of a mile on Monday and two-fifths of a mile on Tuesday. How many miles did she ride altogeth

er?

2 answers:

nlexa [21]3 years ago

8 0

3/5

I'm not sure tho sorry

disa [49]3 years ago

4 0

Answer:

3/5

Step-by-step explanation:

1/5 + 2/5 = 3/5

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1 year ago

How to find the square root

stepladder [879]

Answer:

Step-by-step explanationPaso 1

1 Si el radicando tiene más de dos cifras separamos las cifras en grupos de dos, empezando por la derec2 Calculamos la raíz cuadrada entera o exacta, del primer grupo de cifras por la izquierda, ha.3 El cuadrado de la raíz obtenida 2 (es decir 4) se resta al primer grupo de cifras que aparecen en el radicando Bajamos el siguiente grupo de cifras del radicando, separando del número formado (492) la primera cifra a la derecha (2) y dividiendo lo que resta entre el doble de la raíz 2, es decir 2(2)=4. 5En otra fila debajo de la raíz colocamos el doble de la misma (4). A continuación, se coloca el cociente que se obtenga (9) . Y luego el número obtenido (49) se multiplica por dicho cociente (9). Después, se resta (441) a la cantidad operable (492) del radicando. El cociente obtenido (9) es la segunda cifra de la raíz, quedando (29) Bajamos el siguiente par de cifras y repetimos los pasos anteriores.

Prueba de la raíz cuadrada. Para que el resultado sea correcto, se tiene que cumplir:

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3 years ago

Find a polynomial function whose graph passes through (-1,-3), (0,1), (1,1), and (2,3)

EastWind [94]

Answer:

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Step-by-step explanation:

3 0

3 years ago

How many permutations of the 26 letters of the English alphabet do not contain any of the strings fish, rat, or bird

NARA [144]

The number of permutations of the 26 letters of the English alphabet that do not contain any of the strings fish, rat, or bird is 402619359782336797900800000

Let

$\mathcal{E}=\{\text{All lowercase letters of the English Alphabet}\}\\\\B=\overline{\{b,i,r,d\}} \cup \{bird\}\\\\F=\overline{\{f,i,s,h\}} \cup \{fish\}\\\\R=\overline{\{r,a,t\}} \cup \{rat\}\\\\FR=\overline{\{f,i,s,h,r,a,t\}} \cup \{fish,rat\}$

Then

$Perm(\mathcal{E})=\{\text{All orderings of all the elements of } \mathcal{E}\}\\\\Perm(B)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing bird}\}\\\\Perm(F)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing fish}\}\\\\Perm(R)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing rat}\}\\\\Perm(FR)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing both fish and rat}\}\\$

Note that since

$F \cap R=\varnothing$ , $Perm(F)\cap Perm(R)\ne \varnothing$

But since

$B \cap R \ne \varnothing$ , $Perm(B)\cap Perm(R)= \varnothing$

and

$B \cap F \ne \varnothing$ , $Perm(B)\cap Perm(F)= \varnothing$

Since

$|\mathcal{E} |=26 \text{, then, } |Perm(\mathcal{E})|=26! \\\\|B|=26-4+1=23 \text{, then, } |Perm(B)|=23!\\\\|F|=26-4+1=23 \text{, then, } |Perm(F)|=23!\\\\|R|=26-3+1=24 \text{, then, } |Perm(R)|=24!\\\\|FR|=26-7+2=21 \text{, then, } |Perm(FR)|=21!\\$

where $|Perm(X)|=\text{number of possible permutations of the elements of X taking all at once}$

and

$|Perm(F) \cup Perm(R)| = |Perm(F)| + |Perm(R)| - |Perm(FR)|\\= 23!+24!- 21! \text{ possibilities}$

What we are looking for is the number of permutations of the 26 letters of the alphabet that do not contain the strings fish, rat or bird, or

$|Perm(\mathcal{E})|-|Perm(B)|-|Perm(F)\cup Perm(R)|\\= 26!-23!-(23!+24!- 21!)\\= 402619359782336797900800000 \text{ possibilities}$

This link contains another solved problem on permutations:

brainly.com/question/7951365

6 0

3 years ago

In right triangle PQR PR=17 RQ=15 PQ =8 What is tan P<br><br> What is the answer

Delvig [45]

Answer:

The value of tan P = 1.875

Step-by-step explanation:

Given:

PR=17

RQ=15

PQ =8

To find:

tan P = ?

Solution:

In trigonometric ratio

tan = $\frac{opposite}{adjacent}$

Now on substituting the given values(refer the figure)

tan (P) = $\frac{15}{8}$

tan (P) = 1.875

6 0

3 years ago