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3 years ago

11

terrell wants to drive his car at a speed of 50 miles per hour for 2.75 hours. his car has a fuel efficiency of 25 miles per gal

lon. How many gallons of fuel does terrell need for his journey

2 answers:

nlexa [21]3 years ago

7 0

Terrell will need 5.5 gallons of fuel

myrzilka [38]3 years ago

3 0

He needs 5.5 gallons for the rest of the journey. Hope you find it helpful.

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2 years ago

What to do ??<br> i need help please <br> asap <br> one question left

maks197457 [2]

Answer: $(x^{\frac{2}{7}})(x^{\frac{3}{5}})$

Step-by-step explanation:

If you took the nth root of x, it is the same as raising x to the power of 1/n. Therefore:

$\sqrt[7]{x^{2} } = (x^{2} )^{1/7} = (x^{\frac{2}{7}})\\\sqrt[5]{x^{3} } = (x^{3} )^{1/5} = (x^{\frac{3}{5}})$

And multiply:

$(x^{\frac{2}{7}})(x^{\frac{3}{5}})$

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3 years ago

The defeintion of equivalent ratios

Hitman42 [59]

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8 0

3 years ago

2x−4y=20 whats the answer

alexdok [17]

The answer is

x=10+2y

Steps:

2(x-2y)=20

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4 0

3 years ago

Read 2 more answers

2. Solve the equation using the quadratic<br> formula.<br> -4x2 + 40x + 16 = 0<br> Page 1 of 2

kumpel [21]

The solution to given quadratic equation is x = -0.3851 or x = 10.3851

<em><u>Solution:</u></em>

Given equation is:

$-4x^2 + 40x + 16 = 0$

To find: solve by quadratic equation formula

$\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0\\\\x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Using the above formula,

$\text{ For} -4x^2 + 40x + 16 = 0 \text{ we have } a = -4 ; b = 40 ; c = 16$

<u><em>Substituting the values of a = -4 ; b = 40 ; c = 16 in above quadratic formula we get,</em></u>

$\begin{aligned}&x=\frac{-40 \pm \sqrt{40^{2}-4(-4)(16)}}{2 \times-4}\\\\&x=\frac{-40 \pm \sqrt{1600+256}}{-8}\\\\&x=\frac{-40 \pm 43.081}{-8}\\\\&x=\frac{-40+43.081}{-8} \text { or } x=\frac{-40-43.081}{-8}\\\\&x=-0.3851 \text { or } x=10.3851\end{aligned}$

Thus the solution to given quadratic equation is x = - 0.3851 or x = 10.3851

8 0

3 years ago