Answer:
D=M/V
D=65.1/6.2
Density is 10.5 grams per centimetre cube
Step-by-step explanation:
Volume of cone = (1/3)pi*r²h
56.52 = (1/3)*3.14*r²*6
56.52/(2*3.14) = r²
9 = r²
r² = 9
r = √9
r = 3
Diameter = 2*r = 2*3 = 6 inches. b.
Answer:
90°
Step-by-step explanation:
All sides of the given quadrilateral are 4 units, that is they are equal. Hence it is a RHOMBUS.
Diagonals of a rhombus bisects each other at right angles (90°).
x = 90°
Answer:
the Largest shed dimension is 13.5 ft by 13.5 ft
Largest Area is 182.25 ft²
Step-by-step explanation:
Given that;
Perimeter = 54 ft
P = 2( L + B ) = 54ft
L + B = 54/2
L + B = 27 ft
B = 27 - L ------------Let this be equation 1
Area A = L × B
from equ 1, B = 27 - L
Area A = L × ( 27 - L)
A = 27L - L²
for Maxima or Minima
dA/dL = 0
27 - 2L = 0
27 = 2L
L = 13.5 ft
Now, d²A/dL² = -2 < 0
That is, area is maximum at L = 13.5 using second derivative test
B = 27 - L
we substitute vale of L
B = 27 - 13.5 = 13.5 ft
Therefore the Largest shed dimension = 13.5 ft by 13.5 ft
Largest Area = 13.5 × 13.5 = 182.25 ft²
Yes you are correct, GCF of both terms is x, so you can factor x out.
3x - x² ⇒ x(3 - x)
