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Usimov [2.4K]
3 years ago
14

Solve 7x + 6 < 3(x - 2).

Mathematics
1 answer:
sasho [114]3 years ago
8 0
7x+6=3x-6
    +6       +6
7x+12=3x
-3x       -3x
 4x+12=0
-4x         -4x
 divide both sides by -4 but you have to flip the sign.   
-3>x
or  
{x | x < -3}
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The solutions to the equation 3-k=\sqrt{3k+1} are k = 1 and 8

The given equation is:

3-k=\sqrt{3k+1}

Square both sides of the equation

(3-k)^2=3k+1

Expand the left side of the equation above

(3-k)^2=3k+1\\\\(3-k)(3-k)=3k+1\\\\3^2-3k-3k+k^2=3k+1\\\\9-6k+k^2=3k+1

Write the quadratic equation in standard form

k^2-6k-3k+9-1=0\\\\k^2-9k+8=0\\\\

Factor the quadratic equation

(k-8)(k-1)=0

Use the zero product property

k - 8 = 0

k = 8

k - 1 = 0

k = 1

The solutions to the equation 3-k=\sqrt{3k+1} are k = 1 and 8

Learn more here: brainly.com/question/25840704

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2 years ago
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Step-by-step explanation:

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