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3 years ago

11

Anja collected data about the number of dogs 9th-grade students own. She created this histogram to represent the data and determ

ined that it is skewed right. Which statement is true about Anja’s claim?

2 answers:

fomenos3 years ago

7 0

D. is the correct answer

sattari [20]3 years ago

6 0

D) <span>She is correct; the histogram is skewed to the right because there is less data on the right side.</span>

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Find two consecutive whole numbers that the square root of 105 lies between

erastovalidia [21]

Answer: 10 and 11, also -11 and -10

Sqrt 100 is well known to be 10

Sqrt 121 is 11

Step-by-step explanation:

Positive Sqrt is monotone increasing

So Sqrt 105 is between sqrt 100 and sqrt 121

Second answer

Sqrt 100 is less well known to also be -10

Negative sqrt is monotone decreasing

Sqrt 121 is also -11

Sqrt 105 is also between -121 and -100

4 0

3 years ago

If u answer this correctly u will get a thanks and show

Verizon [17]

61.8 x 1.7 = 105.06

35.80 x 5.6 = 200.48

5 0

3 years ago

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3. Assume all angles are right angles. What is the area of the figure? 12 m 8 m 10 m 16 m 12 m 12 m 1536 square meters b. 408 sq

Svetach [21]

C. 360 Square meters

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3 years ago

Help pls :’( ASAPP!!!<br> “Complete the proof”

nata0808 [166]

1) $\overline{AB} \cong \overline{CD}$ , $\overline{AD} \cong \overline{CB}$ , $\overline{AX} \perp \overline{BD}$ , $\overline{CY} \perp\overline{BD}$ (given)

2) $\overline{BD} \cong \overline{BD}$ (reflexive property)

3) $\triangle ABD \cong \triangle ACDB$ (SSS)

4) $\angle ADB \cong \angle CBY$ (CPCTC)

5) $\angle CYB$ and $\angle AXD$ are right angles (perpendicular lines form right angles)

6) $\triangle CYB$ and $\triangle AXD$ are right triangles (a triangle with a right angle is a right triangle)

7) $\triangle AXD \cong \triangle CYB$ (HA)

8) $\overline{AX} \cong \overline{CY}$ (CPCTC)

6 0

2 years ago

R is inversely proportional to A.

hjlf

Here are the answer: a) R = 3.6 and b) A = 2

Step-by-step explanation:

Given,

R is inversely proportional to A.

R ∝ $\frac{1}{A}$

so, R = $\frac{k}{A}$ -------eq 1 where k is any constant

To find the values of a) R when A = 5 and

b) Value of A when R = 9

Now,

Putting R = 12 and A = 1.5 in eq 1 we get,

12 = $\frac{k}{1.5}$

or, k = 12×1.5 = 18

From eq 1 we get,

R = $\frac{18}{A}$ --------- eq 2

Now,

a) Putting A= 5 in eq 2 we get,

R = $\frac{18}{5}$ = 3.6

b) Putting R = 9 in eq 2 we get

R = $\frac{18}{A}$

or, A = $\frac{18}{9}$ = 2

5 0

3 years ago

Read 2 more answers