Two satellites are in circular orbits around the Earth. Satellite A is at an altitude equal to the Earth's radius, while satelli
1 answer:
You might be interested in
Solution :
Let the positive is along the East and the positive
direction is along the north.
Given :
Mass of the Tesla car, =
Mass of the Ford car,
Now let the initial velocity of Tesla car in the south direction be =
The initial momentum of Tesla car,
Let the initial velocity of Ford car in the east direction be =
So the initial momentum of the Ford car is
Therefore, the initial velocity of both the cars is
Now the final velocity of both the cars is
So the vector form is :
Therefore the momentum after the accident is
According to the law of conservation of momentum, we know
From,
We get,
Therefore the speed of Tesla car before collision = 25.4 m/s
The speed of ford car before collision = 24.4 m/s
Answer:
T= 8.061N*m
Explanation:
The first thing to do is assume that the force is tangential to the square, so the torque is calculated as:
T = Fr
where F is the force, r the radius.
if we need the maximum torque we need the maximum radius, it means tha the radius is going to be the edge of the square.
Then, r is the distance between the edge and the center, so using the pythagorean theorem, r i equal to:
r =
r = 0.5374m
Finally, replacing the value of r and F, we get that the maximun torque is:
T = 15N(0.5374m)
T= 8.061N*m
Explanation:
velocity of disc
lets call (h) 1 m to make it simple.
= 3.614 m/s
m/s pointing towards this:
velocity of hoop=
lets call (h) 1m to make it simple again.
m/s
The disc is the fastest.
While i'm on this subject i'll show you this:
Solid ball
solid disc
hoop
The above is simplified from linear KE + rotational KE, the radius or mass makes no difference to the above formula.
The solid ball will be the faster of the 3, like above i'll show you.
solid ball: velocity
let (h) be 1m again to compare.
m/s
solid disk speed
uniform hoop speed
solid sphere speed