Question

Consider a plywood square mounted on an axis that is perpendicular to the plane of the square and passes through the center of the square. If the square is 0.38 m on a side and is acted on by a 15.0-N force that lies in the plane of the square, determine the magnitude of the maximum torque such a force can produce.
1

Answer 1

Answer:

T= 8.061N*m

Explanation:

The first thing to do is assume that the force is tangential to the square, so the torque is calculated as:

T = Fr

where F is the force, r the radius.

if we need the maximum torque we need the maximum radius, it means tha the radius is going to be the edge of the square.

Then, r is the distance between the edge and the center, so using the pythagorean theorem, r i equal to:

r = $\sqrt{(0.38m)^2+(0.38m)^2}$

r = 0.5374m

Finally, replacing the value of r and F, we get that the maximun torque is:

T = 15N(0.5374m)

T= 8.061N*m