Answer:
work done by the force, W = -147.97 J
Given:
displacement of the box, s = 4.73 m
angle between force and displacement, 
Force, F = 39.7 N
Solution:
Work done by the force can be expressed as the dot product of Force, F and displacement 's' is given by:
W = Fscos
W = 39.7
W = -147.97 J
where negative sign indicates that work is done on the block
Answer: F(t) = 11 - 0.9(t)
Explanation:
We know the following:
The candle burns at a ratio given by:
Burning Ratio (Br) = 0.9 inches / hour
The candle is 11 inches long.
To be able to create a function that give us how much on the candle remains after turning it after a time (t). We will need to know how much of the candle have been burned after t.
Let look the following equation:
Br = Candle Inches (D) / Time for the Candle to burn (T) (1)
Where (1) is similar to the Velocity equation:
Velocity (V) = Distance (D)/Time(T)
This because is only a relation between a magnitude and time.
Let search for D on (1)
D = Br*T (2)
Where D is how much candle has been burn in a specif time
To create a function that will tell us how longer remains of the candle after be given a variable time (t) we use the total lenght minus (2):
How much candle remains? ( F(t) ) = 11 inches - Br*t
F(t) = 11 - 0.9(t)
F(t) defines the remaining length of the candle t hours after being lit
The answer would be number four. I'm sorry if I am too late. Byes.....
Answer:
The force of static friction acting on the luggage is, Fₓ = 180.32 N
Explanation:
Given data,
The mass of the luggage, m = 23 kg
You pulled the luggage with a force of, F = 77 N
The coefficient of static friction of luggage and floor, μₓ = 0.8
The formula for static frictional force is,
Fₓ = μₓ · η
Where,
η - normal force acting on the luggage 'mg'
Substituting the values in the above equation,
Fₓ = 0.8 x 23 x 9.8
= 180.32 N
Hence, the minimum force require to pull the luggage is, Fₓ = 180.32 N
D. to be structural material
