Answer:
(D) 0.006
Step-by-step explanation:
Total number of cards :52
Please note that, all cards have a the possibility of appearing 4 times.
Hence total possible number of a '2' is 4 cards and so it is also for a '10'
Having this Understanding, let's solve the question properly.
The probability that the FIRST CARD is 2 = 4/52
Probability that the second card without replacement is a 10 = 4 / 51
P( 1st two and 2nd four)
4/52 * 4/51 = 4/663
= 0.0060332
Rounding to 3 decimal places = 0.006
Answer:
C.
x -7 -5 -1 1
y 33 31 39 33
Step-by-step explanation:
think so
4/20 simplified would be 1/5. You must know what simplify means first. It means to break down a fraction to its simplest form. So, to simplify 4/20, you must divide 4 from the denominator and numerator. A numerator is a number that is the number above the line. A denominator is the number on the bottom of the line.
Dividing 4 from the denominator and numerator would make it 1/5. Therefore, the answer in simplest form is 1/5. Good luck!
That'd be true only if the value of "s" is the exact same one for both
namely if sec(s) = cos(s)
then solving for "s"
thus
![\bf sec(s)=cos(s)\qquad but\implies sec(\theta)=\cfrac{1}{cos(\theta)} \\\\\\ thus\cfrac{1}{cos(s)}=cos(s)\implies 1=cos^2(s)\implies \pm \sqrt{1}=cos(s) \\\\\\ \pm 1=cos(s)\impliedby \textit{now taking }cos^{-1}\textit{ to both sides} \\\\\\ cos^{-1}(\pm 1)=cos^{-1}[cos(s)]\implies cos^{-1}(\pm 1)=\measuredangle s](https://tex.z-dn.net/?f=%5Cbf%20sec%28s%29%3Dcos%28s%29%5Cqquad%20but%5Cimplies%20sec%28%5Ctheta%29%3D%5Ccfrac%7B1%7D%7Bcos%28%5Ctheta%29%7D%0A%5C%5C%5C%5C%5C%5C%0Athus%5Ccfrac%7B1%7D%7Bcos%28s%29%7D%3Dcos%28s%29%5Cimplies%201%3Dcos%5E2%28s%29%5Cimplies%20%5Cpm%20%5Csqrt%7B1%7D%3Dcos%28s%29%0A%5C%5C%5C%5C%5C%5C%0A%5Cpm%201%3Dcos%28s%29%5Cimpliedby%20%5Ctextit%7Bnow%20taking%20%7Dcos%5E%7B-1%7D%5Ctextit%7B%20to%20both%20sides%7D%0A%5C%5C%5C%5C%5C%5C%0Acos%5E%7B-1%7D%28%5Cpm%201%29%3Dcos%5E%7B-1%7D%5Bcos%28s%29%5D%5Cimplies%20cos%5E%7B-1%7D%28%5Cpm%201%29%3D%5Cmeasuredangle%20s)
