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TiliK225 [7]
3 years ago
9

a park is 4 times as long as it is wide. if the distance around the park is 12.5 kilometers, what is the area of the park

Mathematics
1 answer:
Rom4ik [11]3 years ago
3 0
X -length
y wide

x=4y
2x+2y=12,5

x=4y
8y+2y=12,5

x=4y
y=1,25


x=5
y=1,25


area 
x*y=5*1,25=6,25
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ElenaW [278]

Answer:

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Part 2) a=-\frac{1}{4c^{-6}}

Step-by-step explanation:

Part 1) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2}c^{-2} ----> equation B

substitute equation B in equation A

a=2(-\frac{1}{2}c^{-2})^{3}

Applying property of exponents

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a=2(-\frac{1}{2}c^{-2})^{3}=2(-\frac{1}{2})^3(c^{-2})^{3}=2(-\frac{1}{8})(c^{-6})=-\frac{1}{4c^6}

therefore

a=-\frac{1}{4c^6}

Part 2) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2c^{-2}}=-\frac{c^{2}}{2} ----> equation B

substitute equation B in equation A

a=2(-\frac{c^{2}}{2})^{3}

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(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

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6 0
3 years ago
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garik1379 [7]
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Alenkasestr [34]

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