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Rufina [12.5K]
3 years ago
5

What is the perimeter of 5,7 and 10,12

Mathematics
1 answer:
ANEK [815]3 years ago
4 0
24 and 42, I got this by multiplying 5 and 2 then doing the same thing to 7 and adding the sums. I used this method to find the perimeter of 10 and 12 as well.
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How many flowers spaced every 6in are needed to surround a crcular garden with a 125ft radius?use 3.14 for pi
pychu [463]
What you would do is3.14*r^2 
3.14*125*125 which is 49062.5ft^2
if you need to know how many each 6 inch then you would convert ft to inches which would be 588750in then divide it by 6 which will be 98125 flowers are needed to surround a cicular garden
7 0
3 years ago
The total for shipping charges for the 8 full boxes was $54.75 more than the total for shipping charges for the partially filled
lakkis [162]

Answer:

Step-by-step explanation:

536 because it is correct

4 0
3 years ago
Use the law of cosines to find the value of 2*3*4 cos theta.
daser333 [38]
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3 0
3 years ago
Read 2 more answers
A person who weighs 100 pounds on Earth weighs 16.6 lb. on the moon.
mario62 [17]

Answer:

See explanation below.

Step-by-step explanation:

Given: 100 lbs on Earth is 16.6 lbs on the moon.

a. The independent variable is weight. The gravity of the Moon and the gravity of the Earth are constant. Weight can change, but gravity is a constant.

b. An equation that relates the weight of someone on the Moon who travels to the Earth:

100 / 16.6 = 6.02. Take the Moon weight and multiply by 6.02:

Moon Weight * 6.02 = Earth Weight.

Proof:

16.6 * 6.024 = 99.99 - approximately 100 lbs Earth weight.

c. A 185 lb astronaut on Earth would weigh:

16.6 / 100 = .166. Take the Earth weight and multiply by .166:

185 * .166 = 30 lbs on the Moon.

d. A person who weighs 50 lbs on the Moon:

50 * 6.024 = 301.2 lbs on Earth.

Hope this helps! Have an Awesome Day! :-)

6 0
3 years ago
The half life of radium is 1690 years. if 80 grams are present now, how much will be present in 830 years
Pachacha [2.7K]

Answer:

A(t) = amount remaining in t years

      = A0ekt, where A0 is the initial amount and k is a constant to                     be determined.  

Since A(1690) = (1/2)A0 and A0 = 80,

                we have 40 = 80e1690k

                1/2 = e1690k

                ln(1/2) = 1690k

                k = -0.0004

So, A(t) = 80e-0.0004t

Therefore, A(430) = 80e-0.0004(430)

                           = 80e-0.172

                           ≈ 67.4 g

Step-by-step explanation:

5 0
2 years ago
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