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xz_007 [3.2K]
2 years ago
8

10+____=3 ok this is the last one

Mathematics
2 answers:
lubasha [3.4K]2 years ago
4 0

Answer:

10 + (-7) = 3

Step-by-step explanation:

Since the answer is 3, the missing number has to be negative.

To find it, you need to subtract 10 with 3 and add a negative sign to it.

10 - 3  = 7 = -7

The answer would be -7

LenaWriter [7]2 years ago
3 0

Answer:

10 + 3 = 30

Step-by-step explanation:

that is the answer

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The actual depth of a lake is 15.8 meters.
Anna35 [415]

Answer:

0.2 meters

Step-by-step explanation:

16-15.8 is 0.2 haha

8 0
3 years ago
The number of people in an auditorium can be described by 9^3 how many people are in the auditorium
Advocard [28]
9^3
729
729 people

Answer: 729 people
8 0
3 years ago
Read 2 more answers
If 32 teams participate in a standard single elimination tournament, how many games must be played to decide a champion?
SCORPION-xisa [38]
<h3>Answer: 31 games</h3>

======================================================

Explanation:

  • 32/2 = 16 games will happen in round 1. Afterward, 16 teams are left.
  • 16/2 = 8 games will happen in round 2. Afterward, 8 teams are left.
  • 8/2 = 4 games happen in round 3.
  • 4/2 = 2 games in round 4.
  • 2/2 = 1 game as the final championship.

Count the number of times you divide by two and we have five occurrences of this. So there five rounds overall.

To get the total number of games played, we add up the quotients

16+8+4+2+1 = 31

----------------

Or as a shortcut we can simply subtract off 1 since 1+2+4+...+2^n = 2^(n+1)-1

We can write that rule as

\displaystyle \sum_{k=1}^{n}2^k = 2^{n+1}-1

which is equivalent to

\displaystyle \sum_{k=1}^{n}2^{k-1} = 2^n-1

3 0
3 years ago
Is 3/8 equivalent to 12/24
Ghella [55]
No because 3 x 4 = 12 and 8 x 4 ≠ 24
4 0
2 years ago
What is the solution set of x2 + 5x + 1 = 0?
DerKrebs [107]

Answer:

\huge\boxed{\left\{-\dfrac{5+\sqrt{21}}{2};\ \dfrac{-5+\sqrt{21}}{2}\right\}}

Step-by-step explanation:

x^2+5x+1=0\\\\\text{Use the quadratic formula:}\\\\\text{For}\ ax^2+bx+c=0\\\\\Delta=b^2-4ac\\\\\text{if}\ \Delta < 0,\ \text{then the equation has no real solution}\\\text{if}\ \Delta=0,\ \text{then the equation has one real solution}\ x=\dfrac{-b}{2a}\\\text{if}\ \Delta>0,\ \text{then the equation has two real solution}\ x=\dfrac{-b\pm\sqrt{\Delta}}{2a}

\text{We have}\\\\a=1,\ b=5,\ c=1\\\\\Delta=5^2-4(1)(1)=25-4=21>0\\\\x=\dfrac{-5\pm\sqrt{21}}{2(1)}=\dfrac{-5\pm\sqrt{21}}{2}

3 0
3 years ago
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