A line passes through the two points (-4,6) and (2,-5). 11x +6y - 80 = 0 is the given line equation.
<h3>What is the slope of a line which passes through points ( p,q) and (x,y)?</h3>
Its slope would be:

The slope of parallel lines are same. Slopes of perpendicular lines are negative reciprocal of each other.
The slope m of the line is given as

The equation of a line is

Hence, the equation is 11x +6y - 80 = 0
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2.8x10^-5 ; 2.8x10^-3 ; 2.8 ; 2.8x10^2 ; 2.8x10^4
Answer: an=8+(n-1)(-6) .
Step-by-step explanation:
we have M is durectly porpotional to r^2
so M=(k)r^2
and when r=2, m=14
so 14=(k)(2)^2
k=14/4 =7/2
so when r=12
m= (7/2)(12)^2 =(7/2)(144) = 504
Nancy: 5 Stan: 10
5 is 5 years
younger then Stan
And 5 is twice as
young as 10