Answer:
(a) The standard deviation of your waiting time is 4.33 minutes.
(b) The probability that you will have to wait more than 2 standard deviations is 0.4227.
Step-by-step explanation:
Let <em>X</em> = the waiting time for the bus at the parking lot.
The random variable <em>X</em> is uniformly distributed with parameters <em>a</em> = 0 to <em>b</em> = 15.
The probability density function of <em>X</em> is given as follows:

(a)
The standard deviation of a Uniformly distributed random variable is given by:

Compute the standard deviation of the random variable <em>X</em> as follows:




Thus, the standard deviation of your waiting time is 4.33 minutes.
(b)
The value representing 2 standard deviations is:

Compute the value of P (X > 8.66) as follows:





Thus, the probability that you will have to wait more than 2 standard deviations is 0.4227.
Answer:
84
Step-by-step explanation:
m∠CMT=101-54=47
m∠PMA=37, So
m∠PMA+m∠CMT=47+37=84
The 48 fluid ounce container for sure. The 48 fluid ounce is .05 cents per ounce while the 60 is .06 cents per ounce.
The value of x is 8.
Solution:
Given
.
DG = 60, NQ = 48, DN = 15, NV = x + 4
<u>To find the value of x:</u>
<em>Property of similar triangle:</em>
If two triangles are similar then the corresponding angles are congruent and the corresponding sides are in proportion.


Do cross multiplication.


Subtract 240 from both side of the equation.


Divide by 60 on both sides of the equation.


Hence the value of x is 8.
Figure A has the largest shaded figure because the 4 parts that aren’t covered are less than the other multiple parts of other figures.