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Blizzard [7]
3 years ago
15

Please help me with these questions. Ill mark brainliest to whoever answers correctly!!

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
5 0

Answer:

see below

Step-by-step explanation:

3(i)\\\\AD=?\\\\\cos (\angle BDA)=\frac{AD}{BD}\\\\\cos (27)=\frac{AD}{3}\\\\AD=3\cos 27\\\\AD\approx 2.67

3(ii)\\\\\sin (\angle BCD) = \frac{BD}{CD}\\\\\sin(41)=\frac{3}{CD}\\\\CD=\frac{3}{\sin 41}\\\\CD\approx 4.57

I'm sorry but i have to go I'll come back in half an hour and finish answering

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