Please help me with these questions. Ill mark brainliest to whoever answers correctly!!

Mathematics

1 answer:

LUCKY_DIMON [66]3 years ago

5 0

Answer:

see below

Step-by-step explanation:

$3(i)\\\\AD=?\\\\\cos (\angle BDA)=\frac{AD}{BD}\\\\\cos (27)=\frac{AD}{3}\\\\AD=3\cos 27\\\\AD\approx 2.67$

$3(ii)\\\\\sin (\angle BCD) = \frac{BD}{CD}\\\\\sin(41)=\frac{3}{CD}\\\\CD=\frac{3}{\sin 41}\\\\CD\approx 4.57$

I'm sorry but i have to go I'll come back in half an hour and finish answering

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What is the sum of ? I will put a pic if the answer is correct ill mark brainlist

olga2289 [7]

$\text{The sum of } 1\frac{7}{10} \text{ and } 3\frac{3}{5} \text{ is } 5\frac{3}{10}$

Solution:

Given that we have to find the sum of $1\frac{7}{10} \text{ and } 3\frac{3}{5}$

Let us first convert the mixed fractions to improper fractions

Multiply the whole number part by the fraction's denominator.

Add that to the numerator.

Then write the result on top of the denominator

Therefore,

$1\frac{7}{10} = \frac{10 \times 1 + 7}{10} = \frac{10+7}{10} = \frac{17}{10}\\\\3\frac{3}{5} = \frac{5 \times 3 + 3}{5} = \frac{18}{5}$

Now we can add both the fractions

$1\frac{7}{10} + 3\frac{3}{5} = \frac{17}{10} + \frac{18}{5}$

Make the denominators same

$1\frac{7}{10} + 3\frac{3}{5} = \frac{17}{10} + \frac{18 \times 2}{5 \times 2}\\\\1\frac{7}{10} + 3\frac{3}{5} = \frac{17}{10} + \frac{36}{10}\\\\\text{Add the fractions since the denominator is same }\\\\1\frac{7}{10} + 3\frac{3}{5} = \frac{17+36}{10} = \frac{53}{10}$