All categories

2 years ago

Factor and solve x2 + 7x - 30 = 0. What are the solutions?

Mathematics

2 answers:

skad [1K]2 years ago

6 0

Hey there,

The first step is to factor x² + 7x - 30 = 0:

x² + 10x - 3x - 30
x(x + 10) -3(x + 10)
(x - 3)(x+ 10)

Now we set each factored form equal to 0 and then solve:

x - 3 = 0 -> x = 3
x + 10 = 0 -> x = -10

The factored form would be (x - 3)(x + 10) and the solution would be 3 and -10.

Hope I helped,

Amna

MA_775_DIABLO [31]2 years ago

4 0

(x+10)(x-3). I’m assuming you meant x^2

You might be interested in

Which transformations could have been used to create A'B'C'? Choose all that apply.

Eduardwww [97]

The correct transformation is a rotation of 180° around the origin followed by a translation of 3 units up and 1 unit to the left.

<h3>Which transformation is used to get A'B'C'?</h3>

To analyze this we can only follow one of the vertices of the triangle.

Let's follow A.

A starts at (3, 4). If we apply a rotation of 180° about the origin, we end up in the third quadrant in the coordinates:

(-3, -4)

Now if you look at A', you can see that the coordinates are:

A' = (-4, -1)

To go from (-3, -4) to (-4, -1), we move one unit to the left and 3 units up.

Then the complete transformation is:

A rotation of 180° around the origin, followed by a translation of 3 units up and 1 unit to the left.

If you want to learn more about transformations:

brainly.com/question/4289712

#SPJ1

6 0

1 year ago

A car requires 22 litres of petrol to travel a distance of 259.6 km.Find

Anon25 [30]

Answer:

Step-by-step explanation:

1. A car requires 22 litres of petrol to travel a distance of 259.6 km

what is the distance that the car can travel on 63 ltr of petrol

22ltr = 259.6km

63ltr=

cross multiply

{63 x 259.6}/22 = 16354.8/22 = 743.4 km

A car requires 22 litres of petrol to travel a distance of 259.6 km, it would require 63 ltr of petrol to travel 743.4km

2. To travel a distance of 2013.2 km

we would need to calculate the amount of fuel

A car requires 22 litres of petrol to travel a distance of 259.6 km

what amount of fuel would it require to travel 2013.2km

22ltr = 259.6km

xltr = 2013.2km

x is the value of petrol to cover 2013.2km

cross multiply

(2013.2 x 22)/259.6

44290.4/259.6 = 170.610169492≈170.6 ltr

A car requires 22 litres of petrol to travel a distance of 259.6 km, it would require 170.6 ltr of petrol to travel 2013.2km

if 1ltr is $1.99

170.6 ltr is (170.6 x 1.99)/1 = $339.494≈$339.5

The price of fuel consumed for 2013.2 km at 1 liter of petrol at $1.99 is $339.5

5 0

2 years ago

Please help me It’ll help a lot

Digiron [165]

Answer:

heyy

the answers "20"

Step-by-step explanation:

Okay using the x that we have we find 40 and plug that into the graph and we have 20 :p

7 0

2 years ago

Hey everyone !

zhuklara [117]

Answer:

The measure of the largest angle is 120°

Step-by-step explanation:

<em>Lets explain how to find the measure of an angle from the length of the </em>

<em>sides of the triangle</em>

- We can do that by using the cosine rule

- If the three angles of the triangle are A , B , C, then the side opposite

to angle A is BC , the side opposite to angle B is AC and the side

opposite to angle C is AB, So to find measure of angle A use the rule

$cos(A)=\frac{(AB)^{2}+(AC)^{2}-(BC)^{2}}{2(AB)(AC)}$

<em>Lets solve the problem</em>

- Assume that the triangle is ABC where AB = 14 cm , BC = 10 cm and

AC = 6 cm

- We need to find the measure of the largest angle

- The largest angle is opposite to the longest side

∵ The longest side is AB

∴ The largest angle is C

By using the rule above

∴ $cos(C)=\frac{(AC)^{2}+(BC)^{2}-(AB)^{2}}{2(AC)(BC)}$

∵ AB = 14 cm , BC = 10 cm , AC = 6 cm

∴ $cos(C)=\frac{(6)^{2}+(10)^{2}-(14)^{2}}{2(6)(10)}$

∴ $cos(C)=\frac{36+100-196}{120}$

∴ $cos(C)=\frac{-60}{120}=-0.5$

∴ cos(C) = -0.5 ⇒ that means angle C is obtuse angle

∴ m∠C = $cos^{-1}(-0.5)=120$

* <em>The measure of the largest angle is 120°</em>

8 0

2 years ago

Read 2 more answers

Write a proportion that can be used to find the cost of 10 notebooks if 3 notebooks cost $1.98.

Mariulka [41]

The solution to the problem is as follows:

For 3 notebooks you pay $1.98 so the ratio is 1:0.66.
For 10 notebooks, then we could scale the ratio and it will become 10:6.60. So they will cost you $6.60.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

4 0

3 years ago