Answer: a. 0.1031; fail to reject the null hypothesis
Step-by-step explanation:
Given: Significance level : 
The test statistic in a two-tailed test is z = -1.63.
The P-value for two-tailed test :
[By p-value table]
Since, 0.1031 > 0.05
i.e. p-value > 
So, we fail to reject the null hypothesis. [When p<
then we reject null hypothesis ]
So, the correct option is a. 0.1031; fail to reject the null hypothesis.
The cost of one concert ticket is approximately $148.59.
The tickets sales for the local sales is totalled $101, 244 yesterday.
ticket sales yesterday = $101244
He sold 968 tickets with a two-days total of $143, 836 (both yesterday and today)
The cost of one ticket can be calculated below:
cost of one ticket = 143,836 / 968
cost of one ticket = 148.590909091
cost of one ticket ≈ $ 148.59
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Answer:

Step-by-step explanation:
We are given the following in the question:
x: −4 −3 −2 −1 0
P(X=x): 0.2 0.3 0.1 0.2 0.2
We have to evaluate

Since it is a discrete probability distribution as

We can evaluate the probability as:

Thus, 0.4 is the require probability.
Answer:
4
Step-by-step explanation:
one person is deemed to drive and that person is fixed on the driver's seat no mater which arrangement.
we have now 2 more seats one adjacent to the driver and one rear (two combined).
so the total ways in which all five can be arranged is as follows.
driver, adjacent to him(1) and three back.
driver adjacent to him (different person) and three back.
see the driver is always fixed so we can ignore him.
thus we when driver set fixed , on two remaining seats (adjacent to driver and the back )there can be 4 different combinations.
Answer:
1/5^5
Step-by-step explanation:
Flip the equation into a fraction.
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