RTP: [a tan(u) + b]² + [b tan(u) - a]² = (a² + b²) sec²(u)
Proving LHS = RHS:
LHS = [a tan(u) + b]² + [b tan(u) - a]²
= a² tan²(u) + 2ab tan(u) + b² + b² tan²(u) - 2ab tan(u) + a²
= (a² + b²) tan²(u) + (a² + b²)
= (a² + b²)[tan²(u) + 1]
= (a² + b²) sec²(u), using the identity: tan²(x) + 1 = sec²(x)
= RHS
Answer:
So, area of quadrilateral ABCD = (½ × AC × BE) + (½ × AC × DF) We can calculate the area of different types of quadrilaterals by using the given formula. For the quadrilateral ABCD, if we use centimeter as the unit of measurement, the unit of measure for the area will be cm2 .
I hope it's helpful!
Answer:
28
Step-by-step explanation:
in order to evaluate for the value of x from this 2(x+5)=7x-5 , we will open the bracket and the evaluate for x.
solution
2(x+5)=7x-5
2x + 10 = 7x - 5
collect the like terms together
2x + 10 +5 = 7x
15 = 7x - 2x
15 = 5x
divide both sides by 5
15/5 = 5x/5
3 = x
x =3
so, to evaluate for 2x² + 10
will be
2x² + 10
2 (3)² + 10
2 x 9 + 10
18 + 10
28
Answer:
10 Ghuups I believe. I am sorry if this is wrong
The answer to that question is c
