Answer:
x + x+12 + 3(x+12) = 123
x = 15
Step-by-step explanation:
Jamil : x
Kiera : x+12
Luther : 3 ( x+12)
x + x+12 + 3(x+12) = 123
Distribute
x + x+12 + 3x+36 = 123
Combine like terms
5x+ 48 = 123
Subtract 48 from each side
5x+48-48 = 123-48
5x =75
Divide by 5
5x/5 = 75/5
x = 15
So the answer would be16*4=64
Simplify the complex fractions
A) (from the picture) = 1 2/5.
B) (from the picture) = 13/22
Solve each equation below
A) (from the picture) x= 9
B) (from the picture) w= 10 1/2
C) (from the picture) y= -80
Find the sum of each number below. Describe how you know what the sign of you answer will be.
A) -19 + 8 = -11
B) -6 + (-5) = -11
Answer:
x = 0
Step-by-step explanation:
Subtract 25x^2 from both sides
24x^2 + bx^2 - 25x^2 - 25x^2
Simplify
bx^2 - x^2 = 0
Factor bx^2 - x^2: x^2(b - 1)
bx^2 - x^2
Factor out common term x^2
= x^2 (b - 1)
x^2(b - 1) = 0
Using the Zero Factor Principle: If ab = 0 then a = 0 or b = 0
x^2 = 0
Apply rule x^n = 0 x = 0
x = 0
The values of h and k when f(x) = x^2 + 12x + 6 is in vertex form is -6 and -30
<h3>How to rewrite in vertex form?</h3>
The equation is given as:
f(x) = x^2 + 12x + 6
Rewrite as:
x^2 + 12x + 6 = 0
Subtract 6 from both sides
x^2 + 12x = -6
Take the coefficient of x
k = 12
Divide by 2
k/2 = 6
Square both sides
(k/2)^2 = 36
Add 36 to both sides of x^2 + 12x = -6
x^2 + 12x + 36= -6 + 36
Evaluate the sum
x^2 + 12x + 36= 30
Express as perfect square
(x + 6)^2 = 30
Subtract 30 from both sides
(x + 6)^2 -30 = 0
So, the equation f(x) = x^2 + 12x + 6 becomes
f(x) = (x + 6)^2 -30
A quadratic equation in vertex form is represented as:
f(x) = a(x - h)^2 + k
Where:
Vertex = (h,k)
By comparison, we have:
(h,k) = (-6,-30)
Hence, the values of h and k when f(x) = x^2 + 12x + 6 is in vertex form is -6 and -30
Read more about quadratic functions at:
brainly.com/question/1214333
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