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____ [38]
3 years ago
11

Help me please help I will give you 13 point because this is due help me please

Mathematics
2 answers:
kakasveta [241]3 years ago
8 0

Answer:

IV

Step-by-step explanation:

Zigmanuir [339]3 years ago
4 0

Answer:

Expression 1: 16÷8 has the greatest value.

Step-by-step explanation:

16÷8 =2

whereas,

0.16÷8= 0.02

1.6÷8= 0.2

0.16÷0.8= 0.2

:)

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Find f(0) and f(2) for the given exponential function. f(x) = (1/2)^-x
Aliun [14]
For 0 it will equal 1 because anything to the 0th power is 1 except 0 to the 0.

For 2, It will equal for because when you raise a fraction to the negative power you flip it and that gets rid of the negative number so then you will have 2 to the second and you will get 4.

f (0) = 1, f (2) = 4
8 0
4 years ago
100 POINTS AND BRAINLIST
liberstina [14]

\\ \rm\hookrightarrow sinC=\dfrac{AB}{AC}

\\ \rm\hookrightarrow sinF=\dfrac{DE}{DF}

\\ \rm\hookrightarrow sinZ=\dfrac{XY}{XZ}

As all angles are same

Ratio remains same

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5 0
3 years ago
Write each ratio as a sentence.
RUDIKE [14]
1. There are 2 dogs to every 1 cat.
2. There are 20 students for every 1 teacher.
3. There are 4 sugar cones to every 7 waffle cones.
7 0
3 years ago
Please help!! I need help with this question.
Ainat [17]
Its kinda blurry and I can't read the whole question
4 0
4 years ago
15) A new BMW decreases in value exponentially after it is purchased. If a new BMW is valued at $55,000 and
tia_tia [17]

The values of BMW after 2 years and 4 years  according to the EXPONENTIAL FUNCTION are $33,462 and $20,358.28

Using the parameters given, we define an decreasing exponential function :

A = A_{0} (1 - r)^{t}

Where,

A_{0} = initial amount ; r = Rate ; t = time ; A = final amount

Value after 2 years :

t = 2

A = 55000(1 - 0.22)²

A = 55000(0.78)²

A = $33,462

Value after 4 years :

t = 4

A = 55000(1 - 0.22)^4

A = 55000(0.78)^4

A = $20,358.28

Therefore, the value of BMW after 2 years and 4 years $33,462 and $20,358.28 respectively.

Learn more :

brainly.com/question/14355665

8 0
4 years ago
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