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Inessa [10]
3 years ago
7

NEED ANSWER NOW!!

Mathematics
2 answers:
docker41 [41]3 years ago
7 0
For this case, the first thing we will do is define the following functions:
 Function orange = D (x)
 Blue function = D1 (x)
 Let's see how one function varies with respect to the other:
 D1 (x) = D (x) - 2.5
 Therefore, we see that the function decreases.
 Answer:
 
B. A decrease in demand
VLD [36.1K]3 years ago
7 0
The answer to your question is that it describes the decrease in demand. So option letter B is correct. Letter D is incorrect because it is obvious in the title of thw graph which is only a quantity demanded.
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In the picture below, what is the value of x?
lana [24]

Answer: 9

Step-by-step explanation:Because you have to loom at the answer

5 0
3 years ago
Factor completely 9x2 42x 49. (3x 7)(3x − 7) (9x − 7)(9x − 7) (3x 7)(3x 7) (9x 7)(9x 7).
sweet-ann [11.9K]

Factors of the given expression by splitting middle term of expression9x^2+42x+49 will be (3x+7) and (3x+7).

Given expression is

9x^2+42x+49

<h3>What is a factor?</h3>

A factor is a number that divides another number leaving no remainder

After we split 42x into 21x each,

The expression looks like,

9x^2+21x+21x+49

3x(3x+7)+7(3x+7)\\

Taking 3x+7 as common

(3x+7) (3x+7)

So factors will be (3x+7) and (3x+7).

Therefore,

Factors of the given expression 9x^2+42x+49 will be (3x+7) and (3x+7).

to get more about factors refer to:

brainly.com/question/25829061

6 0
3 years ago
Determine whether the given function is a solution to the given differential equation.
lesantik [10]

Given :

A function , x = 2cos t -3sin t               .....equation 1.

A differential equation , x'' + x = 0      .....equation 2.

To Find :

Whether the given function is a solution to the given differential equation.

Solution :

First derivative of x :

x'=\dfrac{d(2cos t - 3sin t)}{dt}\\\\x'=\dfrac{d(2cost)}{dt}-\dfrac{(3sint)}{dt}\\\\x'=-2sint-3cost

Now , second derivative :

x''=\dfrac{d(-2sint-3cost)}{dt}\\\\x''=-\dfrac{d(2sint)}{dt}-\dfrac{d(3cost)}{dt}\\\\x''=-2cost+3sint

( Note : derivative of sin t is cos t and cos t is -sin t )

Putting value of x'' and x in equation 2 , we get :

=(-2cos t + 3sin t ) + ( 2cos t -3sin t )

= 0

So , x'' and x satisfy equation 2.

Therefore , x function is a solution of given differential equation .

Hence , this is the required solution .

8 0
3 years ago
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Vanyuwa [196]

Answer:

C. Between 4 and 5.......

6 0
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