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3 years ago

Please solve the equation

Mathematics

2 answers:

jeka943 years ago

5 0

Answer:

Mark for review because there is no correct answer.

Step-by-step explanation:

The given expression is

$\frac{4x^2+36}{4x}\times \frac{1}{5x}$

Factor the numerator

$=\frac{4(x^2+9)}{4x}\times \frac{1}{5x}$

Cancel out the common factors

$=\frac{x^2+9}{x}\times \frac{1}{5x}$

We simplify to get

$=\frac{x^2+9}{5x^2}$

victus00 [196]3 years ago

3 0

Answer:

1/5 + 9/5 x^2

None of the listed choices

Step-by-step explanation:

4x^2 +36 1

------------- * ----------

4x 5x

Factor the numerator

4(x^2 +9) 1

------------- * ----------

4x 5x

Cancel the 4

(x^2 +9) 1

------------- * ----------

x 5x

Multiply

(x^2 +9)

-----------------------

5x^2

We can break this into terms

x^2 9

------ + -----------------

5x^2 5x^2

1/5 + 9/5 x^2

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Find the distance between the points (-3, -6) and (5,9). Hint: Use the Pythagorean theorem.

Zinaida [17]

Answer:

The distance between the points (-3, -6) and (5, 9) is 15 units.

Step-by-step explanation:

Given the points

(-3, -6)

(5, 9)

First, we need to find the distance between the two x-coordinates. For this, we need to count the distance from 0 to another point. Then we just add them together.

i.e.

-3 to get to 0 takes 3 units

0 to 5 takes 5 units

3+5=8 units

Just do the same for y-coordinate

From -6 to 0 takes 6 units

0 to 9 takes 9 units

6+9 = 15 units

Therefore, we get the base and height.

Now using the Pythagoras' Theorem to find the distance:

c² = 8² + 15²

c² = 289

$\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}$

$c=\sqrt{289},\:c=-\sqrt{289}$

$c=17,\:c=-17$

As the distance can not be negative.

c = 15 units

Thus, the distance between the points (-3, -6) and (5, 9) is 15 units.

4 0

3 years ago