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Romashka [77]
3 years ago
6

WILL GIVE BRAINLEST

Mathematics
1 answer:
Norma-Jean [14]3 years ago
6 0

Answer:

Part A:at about 1.9 seconds.

Part B: 320 ft

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Answer:An inverse operation are two operations that undo each other addition and subtraction or multiplication and division. You can perform the same inverse operation on each side of an equivalent equation without changing the equality. This gives us a couple of properties that hold true for all equations i guess a little bit of fraction might help if im right idk but forget the fraction part just read the other.


Step-by-step explanation: thats all i got.


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B=a+3 table of values
Lubov Fominskaja [6]
I hope this helps :)

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SashulF [63]

Answer:

M and P

Step-by-step explanation:

they do not cross each other

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AURORKA [14]

Answer:

1)

Minimum is a 4th Degree

2)

Positive; Even

3)

x=-4, -1\text{ Odd Multiplicity}\\x=3\text{ Even Multiplicity}

Step-by-step explanation:

Part 1)

The minimum degree of our function will be 4.

Looking at the graph, we know that the graph crosses the x-axis at -4 and -1. Since it <em>crosses through</em> the x-axis at these two points, these two factors must have an odd multiplicity.

So, it can be anything 1, 3, 5, 7, etc.

However, we will choose the lowest one, 1.

Next, we know that the graph <em>bounces off</em> at 3.

So, it must have an even multiplicity. In other words, 2, 4, 6, 8, etc.

We choose the lowest one, 2.

Therefore, the minimum degree of our function will be 1+1+2 or 4.

Part 2)

The degree of our polynomial is (and will always be) even. Therefore, both ends of the graph will go in the same direction.

Recall the simplest even polynomial, the parent quadratic function. When the leading coefficient is positive, both of the ends go straight up.

This applies to all polynomials with even degrees.

Therefore, since the arms of the graph is going straight up towards positive infinity, the leading coefficient of our graph must be positive.

Part 3)

This is similar to Part 1.

We can see that the graph touches the x-axis at -4, -3, and 1. So, the zeros of the function is: x=-4, -1, 3

We know that it<em> passes through</em> x=-4 \text{ and } x=-1 . So, these two factors must have an odd multiplicity.

However, since the graph <em>bounces off</em> x=3, this factor must have an even multiplicity.

And we're done!

7 0
3 years ago
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