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Zinaida [17]
3 years ago
5

A triangular flag has an area of 187.5 square inches. The base of the flag measures 25 inch How tall is the triangular flag?

Mathematics
1 answer:
SpyIntel [72]3 years ago
6 0
To find the height, you would do the area divided by the base, or in this case,187.5 / 25 which equals 7.5 inches.  Hope this helped!
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Which term does not belong with the other three? AB plane CDE FG HI ​
tatuchka [14]

Answer: your answer should be HI i hope it helps

5 0
3 years ago
A wheel turns through 90 revolutions per minute how many degrees does it turn through in 1 second
suter [353]

Answer:

540°

Step-by-step explanation:

90 revolutions = 360°×90 = 32400°

32400° in 60 sec or 1 min

so, in 1 sec 32400/60 = 540°

7 0
3 years ago
Read 2 more answers
An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t
USPshnik [31]
The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

\displaystyle\int_a^bf(x)\,\mathrm dx

Split up the interval [a,b] into n equal subintervals,

[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]

where a=x_0 and b=x_n. Each subinterval has measure (width) \dfrac{a-b}n.

Now denote the left- and right-endpoint approximations by L and R, respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are \{x_0,x_1,\cdots,x_{n-1}\}. Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, \{x_1,x_2,\cdots,x_n\}.

So, you have

L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)
R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)

Now let T denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)

Factoring out \dfrac12 and regrouping the terms, you have

T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)

which is equivalent to

T=\dfrac12\left(L+R)

and is the average of L and R.

So the trapezoidal approximation for your problem should be \dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2
4 0
3 years ago
Pliz answer this question
irina1246 [14]
Cent is by the hundred so one percent is 1/100 so .6%=6/1000
which can be reduced to 3/500
7 0
3 years ago
Pythagorean theorem , HELPPP
sladkih [1.3K]

Answer:

A=150

Step-by-step explanation:

1/2ab=A

1/2 15x20 = 1/2 300 = 150 = A

Hope this Helps! :)

6 0
3 years ago
Read 2 more answers
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