Answer:
a) y = |x/2 -2| +4
b) y = |x/2 -2| +2
c) y = |(x+1)/2 -2| +3
d) y = |(x-1)/2 -2| +3
Step-by-step explanation:
To translate the function f(x) by (h, k) in the (right, up) direction, you transform it to ...
g(x) = f(x -h) +k
<u>a) one unit up</u>
Add 1 to the function value.

<u>b) one unit down</u>
Subtract 1 from the function value.

<u>c) one unit left</u>
Replace x with x-(-1).

<u>d) one unit right</u>
Replace x with x-1.

Answer:
N(AUC∩B') = 121
The number of students that like Reese's Peanut Butter Cups or Snickers, but not Twix is 121
Step-by-step explanation:
Let A represent snickers, B represent Twix and C represent Reese's Peanut Butter Cups.
Given;
N(A) = 150
N(B) = 204
N(C) = 206
N(A∩B) = 75
N(A∩C) = 100
N(B∩C) = 98
N(A∩B∩C) = 38
N(Total) = 500
How many students like Reese's Peanut Butter Cups or Snickers, but not Twix;
N(AUC∩B')
This can be derived by first finding;
N(AUC) = N(A) + N(C) - N(A∩C)
N(AUC) = 150+206-100 = 256
Also,
N(A∩B U B∩C) = N(A∩B) + N(B∩C) - N(A∩B∩C) = 75 + 98 - 38 = 135
N(AUC∩B') = N(AUC) - N(A∩B U B∩C) = 256-135 = 121
N(AUC∩B') = 121
The number of students that like Reese's Peanut Butter Cups or Snickers, but not Twix is 121
See attached venn diagram for clarity.
The number of students that like Reese's Peanut Butter Cups or Snickers, but not Twix is the shaded part
Answer:
Step-by-step explanation:
denotes the set of elements in both A and C, which is
.
denotes the complement of set B, which is the set of all elements that are in the universal set that are not in set B. In this case, this set is 
The missing exponent of 1/169=(1/13)
So baically
reresent
s=number of studne tickes bouthgt
a=number of adult tickets bought
300 tickest sold
total=300
a+s=300
value=rate times number of peple
student value=4s
adults value=10a
total value=1950
4s+10a=1950
a. system of equations are
s+a=300
4s+10a=1950
b. solve
s+a=300
4s+10a=1950
a+s=300
multiply by -4
-4s-4a=-1200
add to other eqaution
4s+10a=1950
<u>-4s-4a=-1200 + </u>
0s+6a=750
6a=750
divide 6
a=125
subsiute
s+a=300
s+125=300
subtract 125
s=175
a. s+a=300
4s+10a=1950
b. solution above
175 students
125 aduls