Answer:
700pi
Step-by-step explanation:
2pi(10)^2+2pi(10)(25)
'll use the binomial approach. We need to calculate the probabilities that 9, 10 or 11
<span>people have brown eyes. The probability that any one person has brown eyes is 0.8, </span>
<span>so the probability that they don't is 1 - 0.8 = 0.2. So the appropriate binomial terms are </span>
<span>(11 C 9)(0.8)^9*(0.2)^2 + (11 C 10)(0.8)^10*(0.2)^1 + (11 C 11)(0.8)^11*(0.2)^0 = </span>
<span>0.2953 + 0.2362 + 0.0859 = 0.6174, or about 61.7 %. Since this is over 50%, it </span>
<span>is more likely than not that 9 of 11 randomly chosen people have brown eyes, at </span>
<span>least in this region. </span>
<span>Note that (n C r) = n!/((n-r)!*r!). So (11 C 9) = 55, (11 C 10) = 11 and (11 C 0) = 1.</span>
Answer:
Step-by-step explanation:
In propositional logic and Boolean algebra, De Morgan's laws are a pair of transformation rules that are both valid rules of inference. ... The rules allow the expression of conjunctions and disjunctions purely in terms of each other via negation.
2) -88, -45, 5, 40
4) -45, -31, 20, 49
6) -74, -63, -45, 38
8) 18, 27, 27, 58
10) -60, -49, -40, 9
12) -45, -18, 80, 82
The bigger negative numbers are the least because negative numbers work the opposite way around of positive numbers. :)
Answer:
D = -7
Step-by-step explanation:
