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Travka [436]
4 years ago
10

for quadrilateral ABCD, determine the most precise name for it. A(2,3), B(12,3), C(8,6) and D(5,6). Show your work and explain.

Mathematics
2 answers:
Vadim26 [7]4 years ago
7 0
1. Draw the points in the coordinate axes, as in the attached picture.

2. AB and CD are parallel, (both are parallel to the x-axis)

3. A is closer to the y axis than D and C is closer to the C closer than B

4. So combining 2 and 3, we conclude that ABCD is a trapezoid.

5. The remaining thing to check is whether the trapezoid is isosceles or not. For this we drop the heights to AB from points C and D, 

and see that the distances from the feets of these heights to the points A and B are not equal.


Answer: Trapezoid

mina [271]4 years ago
5 0
ABCD is a trapezium. Since line AB and CD do not vary in y, they are parallel. Lines AD and BC are not parallel, as AD increases in x, and BC decreases in x. A quadrilateral with only one set of parallel lines is a trapezium.
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Complete the sequence: 1, 1, 2, 3, 5, ____, ____, ____.
Elza [17]

Answer:

8, 13, 21

Step-by-step explanation:

This is a part of the Fibonacci sequence. it is where you add the two previous numbers together to get the third.

<u><em>Ex. </em></u>

<u><em>1+1 = 2</em></u>

<u><em>1+2 = 3</em></u>

7 0
4 years ago
Marlon withdrew $25 from his savings account every week for 5 weeks. Which expression is the best choice to help him determine t
leva [86]
(25)(5)=125; he withdrew $125
8 0
3 years ago
Cho tam giác ABC cân tại A trung tuyến AM.Biết BC=6cm,AM=4cm .Tính độ dài các cạnh AB và AC
abruzzese [7]

Vì tam giác ABC cân tại A (gt) mà AM là đg trung tuyến nên AM đồng thời là đg cao của t/giác đó:

AM là trung tuyến của t/giác ABC nên M là trung điểm BC:

=> BM =BC/2 =6:2=3(cm)

Xét tam giác AMB vuông tại M

AB^2 =AM^2+BM^2 ( theo định lý Py-ta -go)

7 0
3 years ago
Is -7-5+3=1 true or false
grigory [225]
-7-5+3=1
-12+3=1
-9≠1. As a result, this is False. Hope it help!
7 0
3 years ago
You want to make a rectangular banner that is 18ft. Long with a trim around the entire border of the banner . You have no more t
lys-0071 [83]

Answer:

6 ft

Step-by-step explanation:

Given that:

Length of rectangular banner = 18 ft

Total trim of banner available = 48 ft

To find:

Possible widths of the banner = ?

Solution:

Maximum trim available of the banner around the entire border of the banner = 48 ft

i.e. we are given the total perimeter of the rectangular banner.

Formula for perimeter of a rectangle is given as:

Perimeter = 2 \times (Length + Width)

Putting the values of perimeter and length to find the value of width.

48 = 2 \times (18 + Width)\\\Rightarrow 48 =36+2 \times Width\\\Rightarrow 2 \times Width = 48-36\\\Rightarrow 2 \times Width = 12\\\Rightarrow \bold{Width = 6\ ft}

So, width possible is <em>6ft.</em>

3 0
4 years ago
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