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djverab [1.8K]
3 years ago
6

A _______ is invested by managers in a diversity of stocks, bonds, and other securities. 

Mathematics
2 answers:
Scorpion4ik [409]3 years ago
8 0
A C. MUTUAL FUND is invested by managers in a diversity of stocks, bonds, and other securities.

A mutual fund is an investment vehicle where a pool of funds are collected from numerous investors and are invested in securities like stocks, bonds, money market instruments, and similar assets. It is operated by money managers, who invest the fund capital on the investors behalf.

A. series EE bond - simply a type of bond
B. preferred stock - company shares with special options
D. promissory note - a note that promises to pay a debt
OLEGan [10]3 years ago
3 0

A mutual fund is invested by managers in a diversity of stocks, bonds, and other securities.


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the answer is 16.5cm

just add 15 +1.5 and you get 16.5

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A bag contains 7 red marbles, 8 blue marbles and 4 green marbles. If three marbles
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Brent is a researcher for a food company. He is on a team creating a reduced-calorie version of its flagship cracker. The team w
Andre45 [30]

Answer:

Step-by-step explanation:

Hello!

The research team created a cracker with fewer calories. The average content of calories of the new crackers per serving of 6 should be less than 60.

To test it a random sample of 26 samples of the new cracker was taken and the calories per serving were measured.

Then the study variable is

X: calories of a 6 serve sample of the new reduced-calorie version. (cal)

The variable has a normal distribution with a population standard deviation of 0.82 cal.

To test the claim that the new crackers have on average less than 60 calories, the parameter of interest is the population mean (μ) and the hypotheses are:

H₀: μ ≥ 60

H₁: μ < 60

α: 0.01

Since the variable has a normal distribution and the population variance is known, the best statistic to use to conduct the test is a Standard Normal

Z= \frac{(X[bar]-Mu)}{\frac{Sigma}{\sqrt{n}}  } ~N(0;1)

This test is one tailed to the left, wich means that the null hypothesis will be rejected at low levels of the statistic.

Z_{\alpha } = Z_{0.01} = -2.334

If Z ≤ -2.334, the decision is to reject the null hypothesis.

If Z > -2.334, the decision is to not reject the null hypothesis.

Using the data of the sample I've calculated the sample mean.

X[bar]= ∑X/n= 1548.61/26= 59.56 cal

Z_{H_0}= \frac{(59.56-60)}{\frac{0.82}{\sqrt{26} } } = -2.736

The observed Z value is less than the critical value, so the decision is to reject the null hypothesis.

At a level of significance of 1%, you can conclude that the population mean of calories of the samples of new crackers is less than 60 cal.

I hope it helps!

6 0
3 years ago
Please help! Correct answer only please! I need to finish this assignment by tomorrow.
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Answer:

0.779

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The difference is 10.
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