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3 years ago

6

A _______ is invested by managers in a diversity of stocks, bonds, and other securities.

2 answers:

Scorpion4ik [409]3 years ago

8 0

A C. MUTUAL FUND is invested by managers in a diversity of stocks, bonds, and other securities.

A mutual fund is an investment vehicle where a pool of funds are collected from numerous investors and are invested in securities like stocks, bonds, money market instruments, and similar assets. It is operated by money managers, who invest the fund capital on the investors behalf.

A. series EE bond - simply a type of bond
B. preferred stock - company shares with special options
D. promissory note - a note that promises to pay a debt

OLEGan [10]3 years ago

3 0

A mutual fund is invested by managers in a diversity of stocks, bonds, and other securities.

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Please help me on this question

Mice21 [21]

8+2m^3 is the answer. Hope it help!

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Whoever gets it right can have brainliest but answer ASAP!

DaniilM [7]

Answer:

3 1/3

Step-by-step explanation:

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2 1/2 * 1 1/3 = 20/6

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ANSWER THIS CORRECTLY FOR BRAINLIEST!!!!<br><br> This is 8th grade<br> algebra btw

gulaghasi [49]

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Step-by-step explanation:

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2 years ago

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A. Use composition to prove whether or not the functions are inverses of each other. B. Express the domain of the compositions u

Kryger [21]

Given: $f(x) = \frac{1}{x-2}$

$g(x) = \frac{2x+1}{x}$

A.)Consider

$f(g(x))= f(\frac{2x+1}{x} )$

$f(\frac{2x+1}{x} )=\frac{1}{(\frac{2x+1}{x})-2}$

$f(\frac{2x+1}{x} )=\frac{1}{\frac{2x+1-2x}{x}}$

$f(\frac{2x+1}{x} )=\frac{x}{1}$

$f(\frac{2x+1}{x} )=1$

Also,

$g(f(x))= g(\frac{1}{x-2} )$

$g(\frac{1}{x-2} )= \frac{2(\frac{1}{x-2}) +1 }{\frac{1}{x-2}}$

$g(\frac{1}{x-2} )= \frac{\frac{2+x-2}{x-2} }{\frac{1}{x-2}}$

$g(\frac{1}{x-2} )= \frac{x }{1}$

$g(\frac{1}{x-2} )= x$

Since, $f(g(x))=g(f(x))=x$

Therefore, both functions are inverses of each other.

B.

For the Composition function $f(g(x)) = f(\frac{2x+1}{x} )=x$

Since, the function $f(g(x))$ is not defined for $x=0$ .

Therefore, the domain is $(-\infty,0)\cup(0,\infty)$

For the Composition function $g(f(x)) =g(\frac{1}{x-2} )=x$

Since, the function $g(f(x))$ is not defined for $x=2$ .

Therefore, the domain is $(-\infty,2)\cup(2,\infty)$

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3 years ago

The probability of choosing a winning card from a stack of cards is 5.3%.

drek231 [11]

Answer:

94.7%

Step-by-step explanation:

If it is only winning or losing cards, then you can subtract 5.3 from 100 because probability is out of 100%

100-5.3 = 94.7

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3 years ago