Answer:
30 mph
Step-by-step explanation:
The average speed = Total distance / Total Time
Distance at 45 m/hr.
t = 20 minutes = 20/60 = 1/3 hour.
r = rate = 45 miles / hour
d = r * t
d = 45 * 1/3 = 15 miles.
Average Speed going home.
t = 30 minutes
t = 30 min / 60 min // hour = 1/2 hours
r = 15 miles / 1/2 = 15 * 2 = 30 miles / hr.
To get t on one side, we have to use inverse operations to get rid of the 5.
1. Use inverse operation of multiplication to get rid of 5. Which would be division.
2. Divide both sides by 5.
5t/5 = 7 1/2 / 5
3. Solve.
5t/5 = t and 7 1/2 /5 = 1 1/2
7.5 / 5 = 1.5
Therefore, your answer would be C. divide both sides by 5, and the answer is 1 1/2.
Answer:
look down
Step-by-step explanation:
sam bought 3 pounds so 0.75 multiplied with 3 is 2.25 then we subtract 5.88 by 2.25 to get the original price for 3 pounds which is 3.63. Last step we divide 3.63 by 3 to get the original price for 1 pound and the answer should be 1.21 per pound.
The final equation should be $5.88- $2.25÷3= $1.21
Answer:
Step-by-step explanation:
Suppose the time required for an auto shop to do a tune-up is normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - u)/s
Where
x = points scored by students
u = mean time
s = standard deviation
From the information given,
u = 102 minutes
s = 18 minutes
1) We want to find the probability that a tune-up will take more than 2hrs. It is expressed as
P(x > 120 minutes) = 1 - P(x ≤ 120)
For x = 120
z = (120 - 102)/18 = 1
Looking at the normal distribution table, the probability corresponding to the z score is 0.8413
P(x > 120) = 1 - 0.8413 = 0.1587
2) We want to find the probability that a tune-up will take lesser than 66 minutes. It is expressed as
P(x < 66 minutes)
For x = 66
z = (66 - 102)/18 = - 2
Looking at the normal distribution table, the probability corresponding to the z score is 0.02275
P(x < 66 minutes) = 0.02275
