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vichka [17]
4 years ago
12

An object is launched vertically upward from a 25 foot platform and is modeled by the function s(t)=−16t2+11t+25.

Mathematics
1 answer:
ch4aika [34]4 years ago
4 0

Correct option:

d. 1.64

<h2>Explanation:</h2>

An object is launched vertically upward from a 25 foot platform and is modeled by the following function:

s(t)=-16t^2+11t+25

So this is the equation of a parabola because the object is a projectile so it follows the Projectile Motion.

The object fall back to the ground when s(t)=0 so:

-16t^2+11t+25=0 \\ \\ \\ Using \ quadratic \ formula: \\ \\ t_{12}=\frac{-b\pm \sqrt{b^2-4ac}}{2a} \\ \\ a=-16 \\ \\ b=11 \\ \\ c=25 \\ \\ \\ t_{12}=\frac{-11\pm \sqrt{11^2-4(-16)(25)}}{2(-16)} \\ \\ t_{12}=\frac{-11\pm 41.48}{-32} \\ \\ t_{1}=\frac{-11+ 41.48}{-32}=-0.95s \\ \\ t_{2}=\frac{-11- 41.48}{-32}=1.64s

Since time can't be negative, we only choose the positive value. therefore:

<em>The object fall back to the ground after 1.64 seconds</em>

<em></em>

<h2>Learn more:</h2>

Projectile motion: brainly.com/question/12554459

#LearnWithbrainly

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