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4 years ago

10 + 10 + 10 is equal to 30 40 50 1

Mathematics

1 answer:

vladimir1956 [14]4 years ago

6 0

Answer:

Step-by-step explanation:

10 + 10 = 20 + 10 = 30

Another way is 10 • 3 = 30

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PLS NEED HELP WITH 3 AND 4

Rainbow [258]

Answer:

the first one is 62 and the second one

Step-by-step explanation:

i dont know the second one

3 0

3 years ago

Find the product. 28.5 x 7 A. 198.5 B. 199 C. 199.5 D. 200

aev [14]

Answer:

199.5

Step-by-step explanation:

i know because I added it up

5 0

3 years ago

Read 2 more answers

Find the surface area of a square pyramid with side length 5 ft and slant height 7 ft.

harina [27]

Answer:

99.33ft^2

Step-by-step explanation:

The surface area of a square pyramid is expressed as;

TSA = a²+2a√a²/4 + h²

Given that

a = 5ft

h = 7ft

Substitute

TSA = 5²+2(5)√5²/4 + 7²

TSA = 25+10√25/4 + 49

TSA = 25 + 10√(221/4)

TSA = 25 + 10(√55.25)

TSA = 25 + 10(7.433)

TSA = 25 + 74.33

TSA = 99.33ft^2

Hence the surface area of a square pyramid with side length 5 ft and slant height 7 ft is 99.33ft^2

3 0

3 years ago

Read 2 more answers

How do you find your answer step-by-step?

WARRIOR [948]

5.68 x 6.02 ( 10^9)

same base 10 so add the exponent together

4 0

3 years ago

Can someone please explain how to do this!!!

DedPeter [7]

Hi there!

So we are given that:-

tan theta = 7/24 and is on the third Quadrant.

In the third Quadrant or Quadrant III, sine and cosine both are negative, which makes tangent positive.

Since we want to find the value of cos theta. cos must be less than 0 or in negative.

To find cos theta, we can either use the trigonometric identity or Pythagorean Theorem. Here, I will demonstrate two ways to find cos.

Using the Identity

$\large \displaystyle{ {tan}^{2} \theta + 1 = {sec}^{2} \theta}$

Substitute tan theta = 7/24 in.

$\large \displaystyle{ {( \frac{7}{24}) }^{2} + 1 = {sec}^{2} \theta }$

Evaluate.

$\large \displaystyle{ \frac{49}{576} + 1 = {sec}^{2} \theta} \\ \large \displaystyle{ \frac{625}{576} = {sec}^{2} \theta}$

Reminder -:

$\large \displaystyle{ sec \theta = \frac{1}{cos \theta} }$

Hence,

$\large \displaystyle{ \frac{576}{625} = {cos}^{2} \theta} \\ \large \displaystyle{ \sqrt{ \frac{576}{625} } = cos \theta} \\ \large \displaystyle{ \frac{24}{25} = cos \theta}$

Because in QIII, cos<0. Hence,

$\large \displaystyle \boxed{ \blue{cos \theta = - \frac{24}{25} }}$

Using the Pythagorean Theorem

$\large \displaystyle{ {a}^{2} + {b}^{2} = {c}^{2} }$

Define c as our hypotenuse while a or b can be adjacent or opposite.

Because tan theta = opposite/adjacent. Therefore:-

$\large \displaystyle{ {7}^{2} + {24}^{2} = {c}^{2} } \\ \large \displaystyle{49 + 576 = {c}^{2} } \\ \large \displaystyle{625 = {c}^{2} } \\ \large \displaystyle{25 = c}$

Thus, the hypotenuse side is 25. Using the cosine ratio:-

$\large \displaystyle{cos \theta = \frac{adjacent}{hypotenuse}}$

Therefore:-

$\large \displaystyle{cos \theta = \frac{24}{25} }$

Because cos<0 in Q3.

$\large \displaystyle \boxed{ \red{cos \theta = - \frac{24}{25} }}$

Hence, the value of cos theta is -24/25.

Let me know if you have any questions!

8 0

3 years ago