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3 years ago

If a car can go from 0 to 60 mi/hr in 8.0 seconds, what would be its acceleration ?

Mathematics

1 answer:

tresset_1 [31]3 years ago

6 0

If a car goes from 0 to 60 mph in 8.0 seconds, its acceleration would be 60/8 which is equal to 7.5mph/sec

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Whats the answer to 1/2(5×-8)=-9

REY [17]

Answer:

I do not know if that x is a multiply sign or a variable so I'm going to answer both

If the x is a multiplication sign then the answer is -20 = -9

If the x is a variable then the answer is x = -2

Step-by-step explanation:

1/2(5 * -8) = -9

(1 * 5 * -8)/2 = -9

(5 * -8)/2 = -9

-40/2 = -9

-20 = -9

-20 ≠ -9

1/2(5x - 8) = -9

1(5x -8)/2 = -9

(5x - 8)/2 = -9

2((5x - 8)/2) = -9 * 2

2(5x - 8)/2 = -9 * 2

5x - 8 = -9 * 2

5x - 8 = -18

+8 +8

------------------

5x = -10

x = -10/5

x = -2

5 0

3 years ago

If 180 kg of sugar is to be divided into 3 quantities of ratio 2:3:4 find the smallest and largest quantities.

steposvetlana [31]

Answer:

smallest amount of sugar = 40 kg

largest amount of sugar = 80 kg

Step-by-step explanation:

2 : 3 : 4

2 + 3 + 4 = 9

180 ÷ 9 = 20

Therefore,

2 : 3 : 4 = (2 x 20) : (3 x 20) : (4 x 20) = 40 : 60 : 80

So the smallest amount of sugar = 40 kg

and the largest amount of sugar = 80 kg

4 0

2 years ago

Read 2 more answers

What is the constant of proportionality in the equation y=2/3x

Alexandra [31]

2/3x no y intercept

6 0

3 years ago

Read 2 more answers

Steph,andra,emily,and becca are planning a road trip from their hometown to san antonio

morpeh [17]

Answer:

a. Emily should begin her turn as the third driver at point (1, -0.5).

b. Emily's turn to drive end at point (-2.5, -3.75).

Step-by-step explanation:

Let assume that the group of girls travels from their hometown to San Antonio in a straight line. We know that each location is, respectively:

Hometown

$H(x,y) = (8,6)$

San Antonio

$T(x,y) = (-6,-7)$

Then, we can determine the end of each girl's turn to drive by the following vectorial expression based on the vectorial equation of the line:

Steph

$S(x,y) = H(x,y) + \frac{1}{4}\cdot [T(x,y)-H(x,y)]$ (1)

$S(x,y) = (8,6) + \frac{1}{4}\cdot [(-6,-7)-(8,6)]$

$S(x,y) = (8,6) +\frac{1}{4}\cdot (-14,-13)$

$S(x,y) = (4.5,2.75)$

Andra

$A(x,y) = H(x,y) + \frac{2}{4}\cdot [T(x,y)-H(x,y)]$ (2)

$A(x,y) = (8,6) + \frac{2}{4}\cdot [(-6,-7)-(8,6)]$

$A(x,y) = (8,6)+\frac{2}{4}\cdot (-14,-13)$

$A(x,y) =(1, -0.5)$

Emily

$E(x,y) = H(x,y) + \frac{3}{4}\cdot [T(x,y)-H(x,y)]$ (3)

$E(x,y) = (8,6) + \frac{3}{4}\cdot [(-6,-7)-(8,6)]$

$E(x,y) = (8,6)+\frac{3}{4}\cdot (-14,-13)$

$E(x,y) = (-2.5, -3.75)$

a. If the girls take turns driving and each girl drives the same distance, at what point should they stop from Emily to begin her turn as the third driver?

Emily's beginning point is the Andra's stop point, that is, $A(x,y) =(1, -0.5)$ .

Emily should begin her turn as the third driver at point (1, -0.5).

b. At what point does Emily's turn to drive end?

Emily's turn to drive end at point (-2.5, -3.75).

7 0

3 years ago

The answer for this problem And how to solve it

miss Akunina [59]

Your answer would be $28.02.

3 0

3 years ago