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Tanya [424]
3 years ago
14

Task 4 Task 다. Given: m​

Mathematics
1 answer:
Mariulka [41]3 years ago
7 0

Answer:

where the choices?

Step-by-step explanation:

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For each part, use the Distributive Property to write an equivalent expression
iren2701 [21]

Answer:

The answer is -3x.

Step-by-step explanation:

Combine like terms.

Hope this helps :)

6 0
3 years ago
Read 2 more answers
A set of data has a normal distribution with a mean of 5.1 and a standard deviation of 0.9. Find the percent of data between 4.2
Yuliya22 [10]

A set of data has a normal distribution with a mean of 5.1 and a standard deviation of 0.9. Find the percent of data between 4.2 and 5.1.

Answer: The correct option is B) about 34%

Proof:

We have to find P(4.2

To find P(4.2, we need to use z score formula:

When x = 4.2, we have:

z = \frac{x-\mu}{\sigma}

          =\frac{4.2-5.1}{0.9}=\frac{-0.9}{0.9}=-1

When x = 5.1, we have:

z = \frac{x-\mu}{\sigma}

          =\frac{5.1-5.1}{0.9}=0

Therefore, we have to find P(-1

Using the standard normal table, we have:

P(-1= P(z

                               =0.50-0.1587

                               =0.3413 or 34.13%

                               = 34% approximately

Therefore, the percent of data between 4.2 and 5.1 is about 34%

7 0
3 years ago
The diameter of a circle is 3 meters. What is the circumference?
Gennadij [26K]

Answer:

C≈9.42m

Using any of this formulas

C=2πr

C=2πrd=2r

Solution:

C=πd=π·3≈9.42478m

3 0
3 years ago
What to do when the says of in a problem
s344n2d4d5 [400]
Can you elaborate more on the question?
5 0
2 years ago
Read 2 more answers
For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 10 N acts on
Step2247 [10]

Answer:

The force is 12 N

Step-by-step explanation:

* Lets explain how to solve the problem

- Direct variation is a relationship between two variables that can

 be expressed by an equation in which one variable is equal to a

 constant times the other

- If y ∝ x , then y = kx , where k is the constant of variation

* Lets solve the problem

- The force acting on the object varies directly with the object's

  acceleration

∵ The force is F in newtons and a is the acceleration is m/s²

∴ F ∝ a

∴ F = ka

- To find k substitute F and a by the initial values of them

∵ A force of 10 N acts on a certain object, the acceleration of the

  object is 5 m/s²

∵ F = 10 N when a = 5 m/s²

∵ F = ka

∴ 10 = k(5)

- Divide both sides by 5

∴ K = 2

- Substitute the value of k in the equation

∴ F = 2a

- Lets find the force when the acceleration is 6 m/s²

∵ a = 6 m/s²

∴ F = 2(6) = 12

* The force is 12 N

5 0
2 years ago
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