Question

Complete the point-slope equation of the line through (1,0) and (6,-3).

Answer 1

(1,0),(6,-3)
slope(m) = (-3 - 0) / (6 - 1) = -3/5

y - y1 = m(x - x1)
slope(m) = -3/5
(6,-3)....x1 = 6 and y1 = -3
now sub....and pay attention to ur signs
y - (-3) = -3/5(x - 6)......this is not the final answer....but it seems to be what ur question is asking for.

Answer 2

Answer:

$y-(-3)=-\frac{3}{5}(x-6)$

Step-by-step explanation:

If a line passes through two points $(x_1,y_1)$ and $(x_2,y_2)$, then equation of line is

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

The point slope form of line is

$y-y_1=m(x-x_1)$

where, m is slope.

It is given that the line passes through the points (1,0) and (6,-3).

In the given equation y-(-3)=___, $y_1=-3$. It means

$(x_1,y_1)=(6,-3)$

$(x_2,y_2)=(1,0)$

So, the point slope form of the given line is

$y-(-3)=\frac{0-(-3)}{1-6}(x-6)$

On simplification we get

$y-(-3)=-\frac{3}{5}(x-6)$

Therefore the point slope form of the given line is $y-(-3)=-\frac{3}{5}(x-6)$.