Answer:
146.41
Step-by-step explanation:
third order determinant = determinant of 3×3 matrix A
given ∣A∣=11
det (cofactor matrix of A) =set (transpare of cofactor amtrix of A) (transpare does not change the det)
=det(adjacent of A)
{det (cofactor matrix of A)} ^2 = {det (adjacent of A)}
^2
(Using for an n×n det (cofactor matrix of A)=det (A)^n−1
)
we get
det (cofactor matrix of A)^2 = {det(A) ^3−1
}^2
=(11)^2×2 = 11^4
=146.41
Answer:
C
Step-by-step explanation:
The arrow is pointing right is it is greater than which means that A and B are out. And for
D, -4 is not greater than -3 so D is also out which leaves only C
and -2 is greater than -3
It will be
(4,000) divided by (the value of 4 in the number you left out).
Hi there! I can help you! 8 + (-9) + (-2). When adding negative integers, you have to subtract. 8 - 9 is -1 and -1 - 2 is -3. You would have to start at 8 and go to the left 11 times to land on -3. The sum to the problem is -3.
It is 43 I used calculator
