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Lerok [7]
3 years ago
10

Which expression is equivalent to 9x − 2x + 3 and why?

Mathematics
2 answers:
Marina CMI [18]3 years ago
6 0
Well there's no picture .. but I'll try
9x - 2x + 3
= 7x + 3.. dunno if that's an option
PIT_PIT [208]3 years ago
5 0
9x - 2x = 7x. 7x +3 is the answer. Hope it helps ;) 
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so i don't understand what we are doing at all. i was gone for a week and i missed when we learned about this and i've just been
kumpel [21]
You will need the fraction on “z” to have a common denominator before you can add the two equations. In this equation the common denominator is 6. So you do not change the left side of the equation however the right side turns into -2/6. Now you can add the z’s together and you can also add the integers together.



After simplification I believe the final answer is 1/2z + 1.

I would maybe wait for someone else to answer so that you can be sure because there are other ways to solve this.
6 0
2 years ago
Read 2 more answers
If a baker doubles a recipe that calls for 6-2/3 cups of flour , how many cups of flour will be needed in all ?
Assoli18 [71]
13 1/3 cups needed in all

5 0
3 years ago
Read 2 more answers
How do I draw and determine the equation of a trend line on a scatterplot
Nat2105 [25]

Step-by-step explanation:

Step 1: Draw your trend line.

You begin by drawing your trend line. You want your trend line to follow your data. You want to have roughly half your data above the line and the other half below the line, like this:

trend line equation

Step 2: Locate two points on the line.

Your next step is to locate two points on the trend line. Look carefully at your trend line and look for two easy to figure out points on the line. Ideally, these are points where the trend line crosses a clearly identifiable location.

For the trend line that we just drew, we can see these two easily identifiable points.

trend line equation

We can easily identify these two points as (3, 3) and (12, 6).

Step 3: Plug these two points into the formula for slope.

The formula for slope is this one:

trend line equation

We can label our first point as (x1,y1), and our second point as (x2,y2). So our x1 is 3, our y1 is 3, our x2 is 12, and our y2 is 6. Plugging these values into the equation for slope and evaluating, we get this:

trend line equation

So our slope is 1/3.

8 0
2 years ago
The quadratic function h(t) = -16.1? + 150 models a ball's height, in feet, over time, in seconds,
Sliva [168]
<h2>Hello!</h2>

The answer is: The first graphic representation.

<h2>Why?</h2>

We are given a quadratic equation, meaning that it could be two possible solutions for the exercise, however, we are talking about time, so we have to consider only the obtained positive values.

Let's make the equation equal to 0 in order to find the values of "t"

h(t) = -16.1t^2 + 150

0=-16.1t^2+150

16.1t^2=150

t^2=\frac{150}{16.1} =9.32

t=+-\sqrt{9.32} =+-3.05

t1=3.05

t2=-305

So, discarding the negative value, we can use the possitive value to find the correct graphic representation.

To find the correct graphic representation we must take into consideration the following:

- We must remember that the sign of the coefficient of the quadratic term (t^2) will define if the parabola opens downward or upward.

From the given quadratic (or parabola) equation we have:

a=-1

b=0

c=150

So, since the coefficient of the quadratic term is negative, the parabola opens downward.

- Since we are looking for a graphic that represents the change in height over time, we need to look for a graphic that shows only positive values for the x-axis (time)

- We are looking for a parabola which y-axis intercept is equal to 150.

Therefore, the graphic representation of the quadratic function that models a ball's height over time is the first graphic representation.

Have a nice day!

5 0
2 years ago
5m&lt;6m+6 pls help me ​
torisob [31]

Let's solve your inequality step-by-step.

5m<6m+6

Step 1: Subtract 6m from both sides.

5m−6m<6m+6−6m

−m<6

Step 2: Divide both sides by -1.

−m / −1 < 6 / −1

m>−6

Answer:

m>−6

4 0
2 years ago
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